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Rom4ik [11]
4 years ago
11

Suppose 0.09886 M KOH is titrated into 15.00 mL H2SO4 of unknown concentration until the equivalence point is reached. It takes

a total volume of 29.25 mL KOH to neutralize the H2SO4. How many moles of acid were neutralized during the titration? Express the answer to five significant figures. 0.00028917 moles acid
Chemistry
2 answers:
Alexus [3.1K]4 years ago
4 0

Answer:

0.0014458

Explanation:

edg

Mamont248 [21]4 years ago
3 0

Answer:0.0014458

That’s the right one

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How many types of alkanol do we have
oksano4ka [1.4K]
I think you mean alcohol ? if so there are a few basic types including ethanol
6 0
3 years ago
Un átomo X posee 29 protones y de carga +2 ¿Cuántos electrones tiene?
lesya [120]

Responder:

27

Explicación:

Dado que:

Número de protones en el átomo X = 29

Carga en el átomo X = +2

Si no hay cargo neto;

número de protones = número de electrones

Sin embargo, dado que el átomo X tiene una carga de +2 (dando 2 electrones).

Por lo tanto,

Número de electrones = número de protones - número de carga en el átomo)

Número de electrones = (29 - 2) = 27

4 0
3 years ago
f the Ksp for HgBr2 is 2.8×10−14, and the mercury ion concentration in solution is 0.085 M, what does the bromide concentration
goldfiish [28.3K]

Answer:

0.057 M

Explanation:

Step 1: Given data

Solubility product constant (Ksp) for HgBr₂: 2.8 × 10⁻⁴

Concentration of mercury (II) ion: 0.085 M

Step 2: Write the reaction for the solution of HgBr₂

HgBr₂(s) ⇄ Hg²⁺(aq) + 2 Br⁻

Step 3: Calculate the bromide concentration needed for a precipitate to occur

The Ksp is:

Ksp = 2.8 × 10⁻⁴ = [Hg²⁺] × [Br⁻]²

[Br⁻] = √(2.8 × 10⁻⁴/0.085) = 0.057 M

7 0
3 years ago
When we celebrate a new year we are really celebrating what?
Afina-wow [57]
We are celebrating a fresh start to another year
4 0
3 years ago
How many moles of aluminum are needed to make 9 moles of molecular hydrogen? given the reaction: 2 al + 6 hcl → 2 alcl3 + 3h2 6
sergiy2304 [10]
1) Chemical equation

2Al + 6 HCl ---> 2Al Cl3 + 3 H2

2) molar ratios

2 mol Al : 3 moles H2

3) Proportion

2 mol Al /  3mol H2 = x / 9 mol H2

4) Solve for x

x = 9 mol H2 * 2 mol Al / 3 mol H2 = 6 mol Ag

Answer: 6 moles
7 0
3 years ago
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