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Rom4ik [11]
4 years ago
11

Suppose 0.09886 M KOH is titrated into 15.00 mL H2SO4 of unknown concentration until the equivalence point is reached. It takes

a total volume of 29.25 mL KOH to neutralize the H2SO4. How many moles of acid were neutralized during the titration? Express the answer to five significant figures. 0.00028917 moles acid
Chemistry
2 answers:
Alexus [3.1K]4 years ago
4 0

Answer:

0.0014458

Explanation:

edg

Mamont248 [21]4 years ago
3 0

Answer:0.0014458

That’s the right one

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We know that:
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          = 17.9046 </span>
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<span>V% = Vorg/(Vorg + VH2O) * 100 </span>
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Yotal volume = 30 mL; therefore, 
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<span>(m eug/30) = (4*164/760*18) </span>
<span>m eug = about 1.44g and </span>
<span>
volume = mass/density
            = 1.44/1.05
            = about 1.37 mL </span>
6 0
3 years ago
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