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LekaFEV [45]
3 years ago
7

Help please, wavelengths!:)

Chemistry
2 answers:
kipiarov [429]3 years ago
7 0
The answer is d

because from the point A to point E is considered a full wavelength
meriva3 years ago
3 0
Answer b) a to c would be considered one wavelength.
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What is the volume in liters of 3.51kg of ethylene glycol and density of 1.11g/cm^3?
AVprozaik [17]
D = m/v ---> v = m/d

v = 3162 cm^3
   = <span>0.003162000m^3

</span>
4 0
3 years ago
A fruit juice has a very sour taste. What does this most likely indicate?
gavmur [86]

Explanation:

its hard its either B or C i dont wanna be wrong;-;

6 0
3 years ago
Read 2 more answers
Write one paragraph to explain what circuler motion is?
ZanzabumX [31]

Answer:

When a body moves in a circle with constant speed , it is said to be in uniform circular motion .

Explanation:

  • When an object moves in a circular path , its direction changes at each point .
  • This change in direction result in change of velocity (velocity is vector quantity which changes if direction of the object change) .However speed do not change (it is scalar quantity , not affected by Direction)
  • The Change in velocity produce acceleration ( a = v - u)
  • Hence The object always produce acceleration in uniform circular motion .So, Some force (centripetal force) is needed to keep the object in circular motion.
4 0
3 years ago
A new metal alloy is found to have a specific heat capacity of 0.260 J/(g⋅∘C). First, 47 g of the new alloy is heated to 180. ∘C
Vlad1618 [11]

Answer:

The final temperature, at the equilibrium is 24.14 °C

Explanation:

Step 1: Data given

specific heat capacity of alloy = 0.260 J/(g°C)

MAss of alloy = 47 grams

Mass of water = 110 grams

Specific heat of water = 4.184 J/g°C

Initial temperature of water = 20.0 °C

Initial temperature of alloy = 180.0 °C

Step 2: Calculate the final temperature at equilibrium

Heat lost = heat gained

Qlost = -Qgained

Q(alloy) =- Q(water)

Q=m*c*ΔT

Q = m(alloy)*c(alloy)*ΔT(alloy) = -m(water) * c(water)* ΔT(water)

⇒with m(alloy) = the mass of alloy = 47.0 grams

⇒with c(alloy) = the specific heat of alloy = 0.260 J/g°C

⇒with ΔT(alloy) = the change of temperature = T2- T1 = T2 - 180 °C

⇒with m(water) = the mass of water = 110 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature = T2 - 20.0°C

47.0*0.260 * (T2 - 180.0) = - 110 * 4.184 * (T2 - 20.0)

12.22(T2-180.0) = -460.24(T2- 20)

12.22T2 - 2199.6 = -460.24T2 + 9204.8

472.46T2 = 11404.4

T2 = 24.14 °C

The final temperature, at the equilibrium is 24.14 °C

8 0
3 years ago
For this assignment, the target compound that you should synthesize is 1-methyl-4-nitro-benzene. This is an electrophilic aromat
Liono4ka [1.6K]

Answer:

The methyl group will already be present  

Explanation:

You want to make 1-methyl-4-nitrobenzene.

The question is, "Do I start with the methyl group on the ring and then nitrate, or do I start with the nitro group on the ring and then add the methyl group?"

The methyl group is activating and ortho, para directing.

The nitro group is deactivating and meta directing.

You want a para-substituted product, so you choose to nitrate toluene, as in the reaction scheme below.

 

5 0
4 years ago
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