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3 years ago

Tell uses of nitrogen

Chemistry

1 answer:

Aleksandr [31]3 years ago

6 0

Answer:

Hello

Preservation of Food. Nitrogen gas is used to help with food preservation by preventing oxidative damage leading to food spoiling.
Pharmaceuticals Industry.
Electronics Manufacturing.
Stainless Steel Manufacturing.

Explanation:

thanks

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A substance that increases the concentration of hydroxide ions in aqueous solution.

stepladder [879]

The answer that complete the sentence is "Arrhenius base".

The complete sentence is: A substance that increases the concentration of hydroxide ions in aqueous solution is an Arrhenius base.

Arrhenius' acid and base model says that an acid is a substance that contains hydrogen and ionizes in aqueous solution producing protons (H+) and a base is a substance that cointains hydroxide and release it in aqueous solution.

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3 years ago

00000044m<br> 300000km/s <br> Both in scientific notation

cupoosta [38]

Answer:

4.4 × 10^-7

3 × 10^5

Explanation:

scmack me wit dat brainliest

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2 years ago

What is the formula weight (amu) of the molecule H2O? Use atomic masses of H and O as 1.008 amu and 16.00 amu respectively. Repo

vaieri [72.5K]

Answer:

Formula weight of H₂O molecule is 18.02 amu.

Explanation:

Given data:

Formula weight of H₂O = ?

Atomic mass of H = 1.008 amu

Atomic mass of O = 16.00 amu

Solution:

Formula weight:

"It is the sum of all the atomic weight of atoms present in given formula"

Formula weight of H₂O = 2×1.008 amu + 1×16.00 amu

Formula weight of H₂O = 18.02 amu

Thus, formula weight of H₂O molecule is 18.02 amu.

6 0

3 years ago

If the half life of iridium-182 is 15 years, how much of a 3 gram sample is left after 2 half-lives?

padilas [110]

Answer:

D. 0.75 grams

Explanation:

The data given on the iridium 182 are;

The half life of the iridium 182, $t_{(1/2)}$ = 15 years

The mass of the sample of iridium, N₀ = 3 grams

The amount left, N(t) after two half lives is given as follows;

$N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }$

For two half lives, t = 2 × $t_{(1/2)}$

∴ t = 2 × 15 = 30

$\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2$

$\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75$

∴ The amount left, N(t) = 0.75 grams

4 0

2 years ago

A chemist encounters an unknown metal. They drop the metal into a graduated cylinder containing water, and find the volume chang

Mashutka [201]

Answer:

The density of the metal is 0.561 g/mL

Explanation:

The computation of the density of the metal is shown below;

As we know that

The Density of the metal is

$= \frac{mass}{volume}$

where,

Mass = 4.9g

Change in volume = 6.9 mL

Now place these values to the above formula

So, the density of the metal is

$= \frac{4.9g}{6.9mL}$

= 0.561 g/mL

Hence, the density of the metal is 0.561 g/mL

We simply applied the above formula so that the correct density could arrive

5 0

2 years ago

Tell uses of nitrogen ​

Tell uses of nitrogen