<span><span>LiF, LiCl, LiBr, LiI, LiAtNaF, NaCl, NaBr, NaI, NaAtKF, KCl, KBr, KI, KAt</span><span>RbF, RbCl, RbBr, RbI, RbAt CsF, CsCl, CsBr, CsI, CsAt FrF, FrCl, FrBr, FrI, FrAt<span>
</span></span></span>
D as the two substances could have close boiling points, so if the temperature is not controlled well, both substances will evaporate.
Answer:

Explanation:
Hello!
In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

Therefore, for is to compute the volume of the used base, we proceed as shown below:

And we plug in to obtain:

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Answer:
I believe 11 is B 12 is C 13 is B and 14 is C
Answer:
E = 3.81×10 ⁻²¹ J
Explanation:
Given data:
Frequency of photon = 5.75 ×10¹² Hz
Plancks constant = 6.626 ×10⁻³⁴ Js
Energy of photon = ?
Solution:
E = h×f
E = 6.626 ×10⁻³⁴ Js × 5.75 ×10¹² s⁻¹
E = 38.1×10 ⁻²² J
E = 3.81×10 ⁻²¹ J