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saveliy_v [14]
3 years ago
11

Reply quick pls

Physics
1 answer:
Sholpan [36]3 years ago
4 0
The ball was moving for 0.8seconds
This is because 4/5 x 1 = 0.8

Hope this helps and good luckkkk :)
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Andrea and the other members of the tennis team are practicing hitting tennis balls. If two people hit identical balls at the sa
Pachacha [2.7K]

If two people hit identical tennis balls at the same time, the ball that has the most kinetic energy is the ball that moves at the fastest speed.

<u>Explanation:</u>

The energy possessed by an object by virtue of its motion is called its kinetic energy indicating that only moving objects have kinetic energy. The kinetic energy of an object depends on its speed and mass.

It is given by the expression

K=1/2 mv^2

where m denotes the mass of the object and v denotes its velocity.

since kinetic energy is directly proportional to the square of the velocity, the kinetic energy of an object increases with its velocity.

Hence an object that moves at the fastest speed will have the most kinetic energy.

8 0
3 years ago
A 4.67-g bullet is moving horizontally with a velocity of +357 m/s, where the sign + indicates that it is moving to the right (s
Leni [432]

Answer:

(a)0.531m/s

(b)0.00169

Explanation:

We are given that

Mass of bullet, m=4.67 g=4.67\times 10^{-3} kg

1 kg =1000 g

Speed of bullet, v=357m/s

Mass of block 1,m_1=1177g=1.177kg

Mass of block 2,m_2=1626 g=1.626 kg

Velocity of block 1,v_1=0.681m/s

(a)

Let velocity of the second block  after the bullet imbeds itself=v2

Using conservation of momentum

Initial momentum=Final momentum

mv=m_1v_1+(m+m_2)v_2

4.67\times 10^{-3}\times 357+1.177(0)+1.626(0)=1.177\times 0.681+(4.67\times 10^{-3}+1.626)v_2

1.66719=0.801537+1.63067v_2

1.66719-0.801537=1.63067v_2

0.865653=1.63067v_2

v_2=\frac{0.865653}{1.63067}

v_2=0.531m/s

Hence, the  velocity of the second block after the bullet imbeds itself=0.531m/s

(b)Initial kinetic energy before collision

K_i=\frac{1}{2}mv^2

k_i=\frac{1}{2}(4.67\times 10^{-3}\times (357)^2)

k_i=297.59 J

Final kinetic energy after collision

K_f=\frac{1}{2}m_1v^2_1+\frac{1}{2}(m+m_2)v^2_2

K_f=\frac{1}{2}(1.177)(0.681)^2+\frac{1}{2}(4.67\times 10^{-3}+1.626)(0.531)^2

K_f=0.5028 J

Now, he ratio of the total kinetic energy after the collision to that before the collision

=\frac{k_f}{k_i}=\frac{0.5028}{297.59}

=0.00169

5 0
3 years ago
If you have a block of wood that is 4cm wide ,6cm long and 10cm high and it weighs 100 grams what would happen to the volume if
n200080 [17]
It would make both half 4cm to 2cm wide, and 6cm to 3cm long, 10cm to 5cm hight it would split in half
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A feeding buffer protects ______ path from delays in ______ ____.
Bad White [126]
<span> A feeding buffer protects critical path from delays in non-Critical path

Basically, a feeding buffer acts as a protection for the critical chains from the possible violations in the feeding chains.
By doing this, you would add a protection to the baseline of the deadline of your current projects</span>
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4 years ago
If a car accelerated from 5 m/s to 25 m/s in 10 seconds what is it's acceleration?
Alex_Xolod [135]

Answer:

a= (25-5) /10=2m/s^2

............

6 0
3 years ago
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