The answer is 57.14%.
First we need to calculate molar mass of <span>NaHCO3. Molar mass is mass of 1 mole of a substance. It is the sum of relative atomic masses, which are masses of atoms of the elements.
Relative atomic mass of Na is 22.99 g
</span><span>Relative atomic mass of H is 1 g
</span><span>Relative atomic mass of C is 12.01 g
</span><span>Relative atomic mass of O is 16 g.
</span>
Molar mass of <span>NaHCO3 is:
22.99 g + 1 g + 12.01 g + 3 </span>· <span>16 g = 84 g
Now, mass of oxygen in </span><span>NaHCO3 is:
3 </span>· 16 g = 48 g
mass percent of oxygen in <span>NaHCO3:
48 g </span>÷ 84 g · 100% = 57.14%
Therefore, <span>the mass percent of oxygen in sodium bicarbonate is 57.14%.</span>
The first option: the basic unit of the nervous system
Answer:
9.4 liter
Explanation:
1) Data:
V₁ = 10.0 L
T₁ = 25°C = 25 + 273.15 K = 298.15 K
P₁ = 98.7 Kpa
T₂ = 20°C = 20 + 273.15 K = 293.15 K
P₂ = 102.7 KPa
V₂ = ?
2) Formula:
Used combined law of gases:
PV / T = constant
P₁V₁ / T₁ = P₂V₂ / T₂
3) Solution:
Solve the equation for V₂:
V₂ = P₁V₁ T₂ / (P₂ T₁)
Substitute and compuite:
V₂ = P₁V₁ T₂ / (P₂ T₁)
V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K)
V₂ = 9.4 liter ← answer
You can learn more about gas law problems reading this other answer on
Explanation:
Answer:
B
Explanation:
to conduct scientific exploration of the moon