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3 years ago

The human body produces motion by changing chemical energy into mechanical energy. What happens to the energy

Chemistry

1 answer:

Fantom [35]3 years ago

8 0

Answer:

When you eat food, your body can use the chemical energy in the food to make your muscles move so you can breathe, walk, run, jump, lift things, and do all the other things you need to do to live. The chemical energy in the food gets changed into the mechanical energy of moving muscles.

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What is the molecular formula of ethene and water

nikklg [1K]

Explanation:

ethene C2H4

Water H2O

......

3 0

2 years ago

Help me with this question?!!

Ne4ueva [31]

Answer:

Glow sticks and match would be light emission, slime would be preciptate, and cookies would be gas.

Explanation:

5 0

3 years ago

The rate of effusion of an unknown gas was measured and found to be 11.9 mL/min. Under identical conditions, the rate of effusio

iren2701 [21]

Answer : The correct option is, (B) $CO_2$

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

$R\propto \sqrt{\frac{1}{M}}$

or,

$(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}$ ..........(1)

where,

$R_1$ = rate of effusion of unknown gas = $11.9\text{ mL }min^{-1}$

$R_2$ = rate of effusion of oxygen gas = $14.0\text{ mL }min^{-1}$

$M_1$ = molar mass of unknown gas = ?

$M_2$ = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the above formula 1, we get:

$(\frac{11.9\text{ mL }min^{-1}}{14.0\text{ mL }min^{-1}})=\sqrt{\frac{32g/mole}{M_1}}$

$M_1=44.2g/mole$

The unknown gas could be carbon dioxide $(CO_2)$ that has approximately 44 g/mole of molar mass.

Thus, the unknown gas could be carbon dioxide $(CO_2)$

5 0

3 years ago

Balance the equation and show the calculation of the number of moles and grams of CO2 formed from 11.9 grams of O2. Show your an

n200080 [17]

Answer:

0.2349 moles, 10.3356 g

Explanation:

The given reaction is :

$C_6H_{14}+O_2\rightarrow CO_2 + H_2O$

The balanced reaction by equating the same number of each atom both side is :

$2C_6H_{14}+19O_2\rightarrow 12CO_2 + 14H_2O$

Given that :

Amount of oxygen gas = 11.9 g

Molar mass of oxygen gas = 32 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, moles are:

$moles= \frac{11.9\ g}{32\ g/mol}$

$moles= 0.3719\ mol$

From the reaction,

19 moles of oxygen gas on reaction forms 12 moles of carbon dioxide

Also,

1 mole of oxygen gas on reaction forms 12/19 moles of carbon dioxide

So,

0.3719 moles of zinc on reaction forms $\frac {12}{19}\times 0.3719$ mole of carbon dioxide

<u>Moles of carbon dioxide formed = 0.2349 moles</u>

Mass of carbon dioxide = moles×Molar mass

Molar mass of carbon dioxide = 44 g/mol

<u>Mass of carbon dioxide formed = 0.2349 ×44 g = 10.3356 g</u>

4 0

3 years ago

Aniline involves an amine, which is a Choose... functional group. When an aqueous acid solution is added to an organic solution

Charra [1.4K]

Answer:

Basic

Aqueous

Protonated

Reconstitute

Explanation:

Aniline contains the -NH2 group in which the hydrogen atom bears a lone pair of electrons which is capable of accepting a proton hence aniline is basic.

This lone pair makes it possible for aniline to be protonated to yield an ionic substance which enters into the aqueous phase.

Addition of a base leads to the reconstitution of the aniline.

4 0

3 years ago