1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kvasek [131]
3 years ago
6

Plz hurry fast I need help !!!

Chemistry
2 answers:
NikAS [45]3 years ago
7 0

The Second one is Correct

This is   because there three extra protons (+) than electrons

Vikki [24]3 years ago
5 0

Answer:

USE SOCRATIC

Explanation:

You might be interested in
How can you create low pressure in a capped bottle ?
kiruha [24]
Blow a lot of air into it you can stick an air pump and when your done pumping quickly put tape over the hole
5 0
3 years ago
Calculate the equilibrium constant k for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 k. express your
k0ka [10]
We cannot solve this problem without using empirical data. These reactions have already been experimented by scientists. The standard Gibb's free energy, ΔG°, (occurring in standard temperature of 298 Kelvin) are already reported in various literature. These are the known ΔG° for the appropriate reactions.

<span>glucose-1-phosphate⟶glucose-6-phosphate          ΔG∘=−7.28 kJ/mol
fructose-6-phosphate⟶glucose-6-phosphate          ΔG∘=−1.67 kJ/mol
</span>
Therefore, the reaction is a two-step process wherein glucose-6-phosphate is the intermediate product.

glucose-1-phosphate⟶glucose-6-phosphate⟶fructose-6-phosphate 

In this case, you simply add the ΔG°. However, since we need the reverse of the second reaction to end up with the terminal product, fructose-6-phosphate, you'll have to take the opposite sign of ΔG°.

ΔG°,total = −7.28 kJ/mol  + 1.67 kJ/mol = -5.61 kJ/mol

Then, the equation to relate ΔG° to the equilibrium constant K is

ΔG° = -RTlnK, where R is the gas constant equal to 0.008317 kJ/mol-K.
-5.61 kJ./mol = -(0.008317 kJ/mol-K)(298 K)(lnK)
lnK = 2.2635
K = e^2.2635
K = 9.62


6 0
3 years ago
Read 2 more answers
One of the products of a fermentation reaction is
Alex73 [517]
There are two types of fermentation aerobic and anaerobic. Aerobic are those that need oxygen to ferment while anaerobic are those who do not need oxygen. Products of fermentation are usually water, ethanol, lactic acid and carbon dioxide. Other products are acetone and butyric acid.
5 0
3 years ago
Help! Is there a way to email outlook support for help? If so please comment their email address, as I can't call them on their
CaHeK987 [17]

Answer:

Explanation:

Even if you have a Hotmail email address, you now use the Outlook.com interface to ... I searched and found a Hotmail support number, but is it legit? ... one from Leo's e-mail, I receive a message from windows stating it can't find the site.

7 0
3 years ago
Read 2 more answers
Laurie is moving a dresser with a mass of 250kg. She does 126 J of work with a force of 14 N. How far does she move the dresser?
babunello [35]

9m is the answer to your question


7 0
3 years ago
Other questions:
  • Calorimeter containing 1000 grans of water the initial temperature of water is 24.85 degrees . the heat of water is 4.184 j/g de
    5·1 answer
  • What is the mass of H2O produced when 10.0 grams of H2 reacts completely with 80.0 grams of O2?
    6·1 answer
  • Good morning, I have a question..
    5·1 answer
  • Write the concentration equilibrium constant expression for this reaction.
    11·1 answer
  • CAN SOMEONE HELP ME PLEASE . i have the definitions i just need help with examples
    12·1 answer
  • Please a little help in this I will really appreciate it
    8·1 answer
  • What is the answer pllleeaasseeeee?????
    5·1 answer
  • How many total atoms are in 0.75 moles of CO2
    13·1 answer
  • Can you answer these two questions right please and thank you
    7·1 answer
  • P4+ __02_ P4010 <br> I need help ASAP
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!