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3 years ago

Can anyone answer this with expanation?

Mathematics

1 answer:

shusha [124]3 years ago

3 0

18. ∆PQR =~ ∆RPA ( by SAS )

19. ∆DQR =~ ∆PQR ( by AAS )

20. ∆ARO =~ ∆PQO ( by AAS )

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72% of what number is 27?

Tems11 [23]

72 is 266.666666667% of 27

3 0

2 years ago

Read 2 more answers

PLS HELP ME, I REALLY NEED THIS RIGHT NOW, 100 POINTS, IF YOU ANSWER WITH NO EXPLANATION, OR ANSWER FOR THE POINTS YOU WILL BE R

Reika [66]

9514 1404 393

Answer:

0 ≤ m ≤ 7
0.4541 cm/month; average rate of growth over last 4 months of study

Step-by-step explanation:

Part A:

The study was concluded after 7 months. The fish cannot be expected to maintain exponential growth for any significant period beyond the observation period. A reasonable domain is ...

0 ≤ m ≤ 7

Part B:

The y-intercept is the value when m=0. It is the length of the fish at the start of the study.

Part C:

The average rate of change on the interval [3, 7] is given by ...

(f(7) -f(3))/(7 -3) = (4(1.08^7) -4(1.08^3))/4 = 1.08^3·(1.08^4 -1)

≈ 0.4541 cm/month

This is the average growth rate of the fish in cm per month over the period from 3 months to 7 months.

3 0

2 years ago

According to the latest survey the mean world lifespan is 68.8 years the university of Oregon wants to see if the average life s

pishuonlain [190]

Answer:

Step-by-step explanation:

We would set up the hypothesis test.

For the null hypothesis,

µ = 68.8

For the alternative hypothesis,

µ ≠ 68.8

This is a two tailed test.

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 26,

Degrees of freedom, df = n - 1 = 26 - 1 = 25

t = (x - µ)/(s/√n)

Where

x = sample mean = 72.8

µ = population mean = 68.8

s = samples standard deviation = 2.5

t = (72.8 - 68.8)/(2.5/√26) = 8.16

We would determine the p value using the t test calculator. It becomes

p < 0.00001

Assuming a significance level of 0.05, then

Since alpha, 0.05 > than the p value, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the average life span of the residence of Oregon differs from the world average.

4 0

3 years ago

The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for

Phoenix [80]

Let the price of flowers in September be x, then (100 + 20)/100 * x = $1.50
120/100 * x = $1.50
1.2x = $1.50
x = $1.50/1.2 = $1.25
The price of flowers in September is $1.25

Total money realised in September = $1.25 x 900 = $1,125
40% earned = 0.4 x $1,125 = $450

Total money realised in October = $1.50 x 700 = $1,050
40% earned = 0.4 x $1,050 = $420

The class earned more money in September and they earned $30 more than in October.

5 0

3 years ago

1. Marlene is going on a camping trip with a group of friends. She brings 3 boxes of granola bars,

andrey2020 [161]

Answer:

13.5

Step-by-step explanation:

total boxes of granola is = 3 + 2 + 1

= 6 boxes

6 boxes = 57 bars

1 box = 57 / 6

1 box = 9.5 + 3

= 13.5 (ANS)

i hope my ans is correct if not i apologise.

3 0

2 years ago

Read 2 more answers

Can anyone answer this with expanation?​

Can anyone answer this with expanation?