Explanation:
P1= 44 kpa
P2= 50 kpa
V1= 4.50 L
V2= ?
P1 V1= P2 V2
44 × 4.50 = 50 × V2
198= 50 × V2
V2 = 198/ 50
V2= 3.96 L "the new volume"
 
        
             
        
        
        
Answer:
- <u><em>g) Neither plant should increase by 1 cm in height.</em></u>
Explanation:
See the graph for this question on the figure attached.
The growing of the <em>plant A</em> is represented by the line that goes above the other. At start, that line has a slope that rises about 0.75 cm ( height increase) in 1 day. From the day 2 and forward the slope of the line decreases. The line reaches its highest point about at day 4 and seems to start decreasing. Thus, you should predict that on the day six it <em>most likely </em>does not increase in height.
The growing of the <em>plant B</em> is represented by the line drawn below the other. As for the plant B, the growing decreases with the number of days. Between the days 4 and 5 the line is almost flat, which means that <em>most likely</em> this plant will not grow on the day six or grow less than 0.5 cm.
Thus, for both plants you can say that <em>on day six, most likley, neither should increase by 1 cm in height (</em>option g).
 
        
             
        
        
        
Answer:
= 97.44 Liters at S.T.P
Explanation:
The reaction between Iron (iii) oxide and Carbon monoxide is given by the equation; 
Fe2O3(s)+ 3CO(g) → 3CO2(g) + 2Fe(s)
 From the reaction when the reactants react, 2 moles of Fe and 3 moles of CO2 are produced.
Therefore; Mole ratio of Iron : Carbon dioxide is 2:3 
Thus; Moles of Carbon dioxide = (2.9/2)×3 
                                                    = 4.35 moles 
But; 1 mole of CO2 at s.t.p occupies 22.4 liters 
Therefore; 
Mass of CO2 = 22.4 × 4.35 Moles 
                      = 97.44 L