<h3>
Answer:</h3>
82.11%
<h3>
Explanation:</h3>
We are given;
- Theoretical mass of the product is 137.5 g
- Actual mass of the product is 112.9 g
We are supposed to calculate the percentage yield
- We need to know how percentage yield is calculated;
- To calculate the percentage yield we get the ratio of the actual mass to theoretical mass and express it as a percentage.
Thus;
% yield = (Actual mass ÷ Experimental mass) × 100%
= (112.9 g ÷ 137.5 g) × 100%
= 82.11%
Therefore, the percentage yield of the product is 82.11 %
When the reaction equation is:
Cu 2+(aq) + 2 e- → Cu(S)
from the reaction equation, we can see that each 1 mole of Cu 2+ need 2 moles e-
So, the moles of e- when we have 5 moles copper = 5* 2 = 10 moles
by using this formula we can get the time directly:
time(per sec) = moles of e- * faraday's constant * current
= 10 moles * 96500 coul/mol * 1 sec / 50 coul
= 19300 sec
= 19300 /(60*60) = 5.36 Hours
∴ the answer will be a) 5.36 Hours
The atomic number for oxygen is 8.
