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Lorico [155]
2 years ago
8

If 7.4 moles of carbon dioxide is produced in this reaction, how many moles of oxygen gas would be needed?

Chemistry
1 answer:
Nimfa-mama [501]2 years ago
4 0

Answer:

11.6 mol O₂

Explanation:

  • C₇H₁₆ + 11 O₂ → 7 CO₂ + 8 H₂O

In order to solve this problem we need to <u>convert moles of carbon dioxide (CO₂) into moles of oxygen gas (O₂)</u>. To do so we'll use a conversion factor containing the <em>stoichiometric coefficients</em> of the balanced reaction:

  • 7.4 mol CO₂ * \frac{11molO_2}{7molCO_2} = 11.6 mol O₂
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How many grams are in 8.3 moles of CaCl2?
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(8.3×40)+(8.3×71)

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Hydrogen produced from a hydrolysis reaction was collected over water and the following data was compiled.
Shkiper50 [21]

Answer:

  • 0.00358 mol

Explanation:

<u>1) Data:</u>

a) V = 93.90 ml

b) T = 28°C

c) P₁ = 744 mmHg

d) P₂ = 28.25 mmHg

d) n = ?

<u>2) Conversion of units</u>

a) V = 93.90 ml × 1.000 liter / 1,000 ml = 0.09390 liter

b) T = 28°C = 28 + 273.15 K = 301.15 K

c) P₁ = 744 mmHg × 1 atm / 760 mmHg = 0.9789 atm

d) P₂ = 28.5 mmHg × 1 atm / 760 mmHg = 0.0375 atm

<u>3) Chemical principles and formulae</u>

a) The total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas. Hence, the partical pressure of the hydrogen gas collected is equal to the total pressure less the vapor pressure of water.

b) Ideal gas equation: pV = nRT

<u>4) Solution:</u>

a) Partial pressure of hydrogen gas: 0.9789 atm - 0.0375 atm = 0.9414 atm

b) Moles of hygrogen gas:

pV = nRT ⇒ n = pV / (RT) =

n =  (0.9414 atm × 0.09390 liter) / (0.0821 atm-liter /K-mol × 301.15K) =

n = 0.00358 mol (which is rounded to 3 significant figures) ← answer

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3 years ago
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A farmer uses water to irrigate his potato crops. Which roles of water does this examplify
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Answer:

This exemplifies the agricultural role of water.

Explanation:

7 0
2 years ago
While you were "sweating" your chemistry test, water vapor evaporates from your body, absorbing 50,000 J of energy. (assume no
TiliK225 [7]

Answer:

\boxed {\boxed {\sf B. \ 22 \ grams}}

Explanation:

We need to use the formula for heat of vaporization.

Q=H_{vap}*m

Identify the variables.

  • The heat absorbed by the evaporating water is the <u>latent heat of vaporization. </u>For water, that is 2260 Joules per gram.
  • Q is the energy, in this problem, 50,000 Joules.
  • m is the mass, which is unknown.

H_{vap}=2260 \ J/g\\Q=50,000 \ J \\

Substitute the values into the formula.

50,000 \ J=2260 \ J/g*m

We want to find the mass. We must isolate the variable, m.

m is being multiplied by 2260 J/g. The inverse operation of multiplication is division. Divide both sides by 2260 J/g.

\frac{50,000 \ J}{2260 \ J/g} =\frac{2260 \ J/g*m}{2260 \ J/g}

\frac{50,000 \ J}{2260 \ J/g} =m

Divide. Note that the Joules (J) will cancel each other out.

\frac{50,000 \ }{2260 \ g} =m

22.1238938 \ g =m

Round to the nearest whole number. The 1 in the tenth place tells us to leave the number as is.

22 \ g \approx m

The mass is about 22 grams, so choice B is correct.

3 0
2 years ago
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