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3 years ago

If 7.4 moles of carbon dioxide is produced in this reaction, how many moles of oxygen gas would be needed?

Chemistry

1 answer:

Nimfa-mama [501]3 years ago

4 0

Answer:

11.6 mol O₂

Explanation:

C₇H₁₆ + 11 O₂ → 7 CO₂ + 8 H₂O

In order to solve this problem we need to convert moles of carbon dioxide (CO₂) into moles of oxygen gas (O₂). To do so we'll use a conversion factor containing the stoichiometric coefficients of the balanced reaction:

7.4 mol CO₂ * $\frac{11molO_2}{7molCO_2}$ = 11.6 mol O₂

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A student investigated how much solid was dissolved in sea water.

SashulF [63]

Answer:

weighing balance/analytical balance

Graduated cylinder/buret

Explanation:

The mass of the evaporating basin could be measured using a weighing balance or an analytical balance. Both are classified as weighing scales but the analytical balance can measure the mass of objects up to 4 decimal places, thus, providing better accuracy in measurement than ordinary weighing balance that can only measure up to 2 decimal places.

In order to measure 50 cm3 of the sea water, a graduated cylinder or a buret can be used. Both equipment can measure up to the same decimal places and, thus, have virtually the same accuracy.

3 0

2 years ago

Which element is a noble gas? A. W B. Ar C. N D. Er

inessss [21]

His the answer I hope it helps

3 0

3 years ago

Plz Help Will Upvote

My name is Ann [436]

A.heliumHydrogen is the most abundant element in the Universe; helium is second. However, after this, the rank of abundance does not continue to correspond to the atomic number; oxygen has abundance rank 3, but atomic number 8.

3 0

3 years ago

PLEASE HELP!!

grandymaker [24]

Answer:

1. 136 °C.

2. 0.21 atm.

Explanation:

1. Determination of the new temperature in °C.

Initial volume (V1) = 1.35L

Final volume (V2) = 1.95L

Initial temperature (T1) = 283 K

Final temperature (T2) =...?

Using the Charles' law equation, the new temperature of the gas can be obtained as follow:

V1 /T1 = V2 /T2

1.35/283 = 1.95/T2

Cross multiply

1.35 × T2 = 283 × 1.95

1.35 × T2 = 551.85

Divide both side by 1.35

T2 = 551.85/1.35

T2 = 408.8 ≈ 409 K

Finally, we shall convert 409 K to °C. This can be obtained as follow:

T (°C) = T(K) – 273

T(K) = 409 K

T (°C) = 409 – 273

T (°C) = 136 °C

Therefore, the new temperature of the gas is 136 °C.

2. Determination of the new pressure.

Initial pressure (P1) = 1.34 atm

Initial volume (V1) = 267 mL

Final volume (V2) = 1.67 L

Final pressure (P2) =.?

Next, we shall convert 1.67 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

1.67 L = 1.67 L × 1000 mL / 1 L

1.67 L = 1670 mL

Therefore, 1.67 L is equivalent to 1670 mL.

Finally, we shall determine the new pressure of the gas as follow:

Initial pressure (P1) = 1.34 atm

Initial volume (V1) = 267 mL

Final volume (V2) = 1670 mL

Final pressure (P2) =.?

P1V1 = P2V2

1.34 × 267 = P2 × 1670

357.78 = P2 × 1670

Divide both side by 1670.

P2 = 357.78 / 1670

P2 = 0.21 atm.

Therefore, the new pressure of the gas is 0.21 atm.

3 0

3 years ago

Chloroform is a liquid once used for anesthetic. What is the volume of 5.0 g of chloroform? The density of chloroform 1.49 g/mL

mario62 [17]

Answer:

3.3557047 mL

Explanation:

The density can be found using the following formula:

$d=\frac{m}{v}$

Let's rearrange the formula to find the volume, $v$ .

$d*v=\frac{m}{v}*v$

$d*v=m$

$\frac{d*v}{d} =\frac{m}{d}$

$v=\frac{m}{d}$

The volume can be found by dividing the mass by the density. The mass of the chloroform is 5 grams and the density is 1.49 grams per milliliter. Therefore,

$m= 5g \\d= 1.49 g/mL$

Substitute the values into the formula.

$v=\frac{5g}{1.49 g/mL}$

Divide. When we divide, the grams, or g, in the numerator and denominator will cancel out.

$v= \frac{5}{1.49}mL$

$v=3.3557047 mL$

The volume of 5 grams of chloroform is 3.3557047 milliliters

4 0

3 years ago