Answer:
Δr=20.45 %
Explanation:
Given that
Rake angle α = 15°
coefficient of friction ,μ = 0.15
The friction angle β
tanβ = μ
tanβ = 0.15
β=8.83°
2φ + β - α = 90°
φ=Shear angle
2φ + 8.833° - 15° = 90°
φ = 48.08°
Chip thickness r given as


r=0.88
New coefficient of friction ,μ' = 0.3
tanβ' = μ'
tanβ' = 0.3
β'=16.69°
2φ' + β' - α = 90°
φ'=Shear angle
2φ' + 16.69° - 25° = 90°
φ' = 49.15°
Chip thickness r' given as


r'=0.70
Percentage change


Δr=20.45 %
Answer:
Option D - the moisture content at turbine exit will decrease
Explanation:
In an ideal rankine system, the phenomenon of superheating occurs at a state where the vapor state of the fluid is heated above its saturation temperature and the phase of the fluid is changed from the vapor phase to the gaseous phase.
Now, a vapour phase has two different substances at room temperature, whereas a gas phase consists of just a single substance at a defined thermodynamic range, at standard room temperature.
At the turbine exit, since it's just a single substance in gaseous phase, it means it will have less moisture content.
Thus, the correct answer is;the moisture content at turbine exit will decrease
Answer: False
Explanation:
The statement that "a person hired by a pharmaceutical company to streamline the company’s drug production process would most likely be an electrical engineer" is false.
An electrical engineer is an engineer that designs, and tests electrical equipment like smartphones, electric motors, etc. The person designs equipments which makes use of electricity or electronics.
He or she doesn't streamline the company’s drug production process, this can be the role played by the production manager.
Solution :
Given :
k = 0.5 per day


Volume, V 
Now, input rate = output rate + KCV ------------- (1)
Input rate 


The output rate 
= ( 40 + 0.5 ) x C x 1000

Decay rate = KCV
∴
= 1.16 C mg/s
Substituting all values in (1)

C = 4.93 mg/L
Answer:
209.55 ft
Explanation:
Given Data:
Benchmark:
Reduced Level or Elevation = 210.50
Height of Instrument = Reduced Level + Back sight Reading
Height of Instrument = 210.50 + 3.57 = 214.07 ft
Turning Point:
Back sight Reading = 2.91 ft
Fore Sight Reading = 4.52
Reduced Level or Elevation of Turning Point = Height of Instrument – fore sight Reading
Reduced Level or Elevation of Turning Point = 214.07 – 4.52 = 209.55 ft
Height of Instrument at Turning Point = Reduced Level + Back sight Reading
Height of Instrument at Turning Point = 209.55 + 2.91 = 212.46 ft