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Cerrena [4.2K]
3 years ago
7

What is one experiment that has been done in the manufacturing

Engineering
1 answer:
Bingel [31]3 years ago
8 0
Do you have a picture of any sort so I can see if there’s any options ;)
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Assume that in orthogonal cutting the rake angle is 15° and the coefficient of friction is 0.15. a. Determine the percentage cha
alexira [117]

Answer:

Δr=20.45 %

Explanation:

Given that

Rake angle α =  15°

coefficient of friction ,μ = 0.15

The friction angle β

tanβ = μ

tanβ = 0.15

β=8.83°

2φ +  β - α  = 90°

φ=Shear angle

2φ + 8.833° - 15° = 90°

φ = 48.08°

Chip thickness r given as

r=\dfrac{tan\phi}{cos\alpha +sin\alpha\ tan\phi}

r=\dfrac{tan48.08^{\circ}}{cos15^{\circ} +sin15^{\circ}\ tan48.08^{\circ}}

r=0.88

New coefficient of friction ,μ'  = 0.3

tanβ' = μ'

tanβ' = 0.3

β'=16.69°

2φ' +  β' - α  = 90°

φ'=Shear angle

2φ' + 16.69° - 25° = 90°

φ' = 49.15°

Chip thickness r' given as

r'=\dfrac{tan\phi'}{cos\alpha +sin\alpha\ tan\phi'}

r'=\dfrac{tan44.15^{\circ}}{cos49.15^{\circ} +sin49.15^{\circ}\ tan44.15^{\circ}}

r'=0.70

Percentage change

\Delta r=\dfrac{r-r'}{r}\times 100

\Delta r=\dfrac{0.88-0.70}{0.88}\times 100

Δr=20.45 %

8 0
3 years ago
Consider a simple ideal Rankine cycle with fixed boiler and condenser pressures. If the steam is superheated to a higher tempera
Usimov [2.4K]

Answer:

Option D - the moisture content at turbine exit will decrease

Explanation:

In an ideal rankine system, the phenomenon of superheating occurs at a state where the vapor state of the fluid is heated above its saturation temperature and the phase of the fluid is changed from the vapor phase to the gaseous phase.

Now, a vapour phase has two different substances at room temperature, whereas a gas phase consists of just a single substance at a defined thermodynamic range, at standard room temperature.

At the turbine exit, since it's just a single substance in gaseous phase, it means it will have less moisture content.

Thus, the correct answer is;the moisture content at turbine exit will decrease

4 0
3 years ago
PLEASE HELP AND ANSWER MY OTHER QUESTIONS!,
NARA [144]

Answer: False

Explanation:

The statement that "a person hired by a pharmaceutical company to streamline the company’s drug production process would most likely be an electrical engineer" is false.

An electrical engineer is an engineer that designs, and tests electrical equipment like smartphones, electric motors, etc. The person designs equipments which makes use of electricity or electronics.

He or she doesn't streamline the company’s drug production process, this can be the role played by the production manager.

8 0
3 years ago
A lake is fed by a polluted stream and a sewage outfall. The stream and sewage wastes have a decay rate coefficient (k) of 0.5/d
joja [24]

Solution :

Given :

k = 0.5 per day

$C_s = 10 \ mg/L \ ; \ \ Q_s= 40 \ m^3/s$

$C_{sw} = 100 \ ppm \ ; \ \ Q_{sw}= 0.5 \ m^3/s$

Volume, V $= 200 \ m^3$

Now, input rate = output rate + KCV ------------- (1)

Input rate  $= Q_s C_s + Q_{sw}C_{sw}$

                $=(40 \times 10) + (0.5\times 100)$

                $= 2 \times 10^5 \ mg/s$

The output rate $= Q_m C_{m}$

                          = ( 40 + 0.5 ) x C x 1000

                          $=40.5 \times 10^3 \ C \ mg/s$

Decay rate = KCV

∴$KCV =\frac{0.5/d \times C \  \times 200 \times 1000}{24 \times 3600}$

            = 1.16 C mg/s

Substituting all values in (1)

$2 \times 10^5 = 40.5 \times 10^3 \ C+ 1.16 C$

C = 4.93 mg/L

4 0
3 years ago
A digital automatic level is used to profile a road centerline. The backsight reading is 3.57 ft on BM #1, which has an elevatio
liubo4ka [24]

Answer:

209.55 ft

Explanation:

Given Data:

Benchmark:

Reduced Level or Elevation = 210.50

Height of Instrument = Reduced Level + Back sight Reading

Height of Instrument = 210.50 + 3.57 = 214.07 ft

Turning Point:

Back sight Reading = 2.91 ft

Fore Sight Reading = 4.52

Reduced Level or Elevation of Turning Point = Height of Instrument – fore sight Reading

Reduced Level or Elevation of Turning Point = 214.07 – 4.52 = 209.55 ft

Height of Instrument at Turning Point = Reduced Level + Back sight Reading

Height of Instrument at Turning Point = 209.55 + 2.91 = 212.46 ft

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4 0
3 years ago
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