Answer:
40 ft
Explanation:
Assuming no loss of energy in the system of pulleys, the work done is the same whether you move the load directly or through the pulleys.
W = Fd . . . . . . . . work is the product of force and distance
F(10 ft) = (0.25F)(d) . . . . . where d is the distance we want to find
d = 10F/(0.25F) = 40
The rope will need to move 40 feet.
Answer:
- hoop stress
- longitudinal stress
- material used
all this could led to the failure of the garden hose and the tear along the length
Explanation:
For the flow of water to occur in any equipment, water has to flow from a high pressure to a low pressure. considering the pipe, water is flowing at a constant pressure of 30 psi inside the pipe which is assumed to be higher than the allowable operating pressure of the pipe. but the greatest change in pressure will occur at the end of the hose because at that point the water is trying to leave the hose into the atmosphere, therefore the great change in pressure along the length of the hose closest to the end of the hose will cause a tear there. also the other factors that might lead to the failure of the garden hose includes :
hoop stress ( which acts along the circumference of the pipe):
αh = EQUATION 1
and Longitudinal stress ( acting along the length of the pipe )
αl = EQUATION 2
where p = water pressure inside the hose
d = diameter of hose, T = thickness of hose
we can as well attribute the failure of the hose to the material used in making the hose .
assume for a thin cylindrical pipe material used to be
≥ 20
insert this value into equation 1
αh = = 60/2 = 30 psi
the allowable hoop stress was developed by the material which could have also led to the failure of the garden hose
Answer:
The belt in an open belt drive travels from one pulley's top to the top of another without intersecting. In cross belt drive, the belt crosses itself by moving from the top of one pulley to the bottom of another. Every revolution, the entire belt remains in the same plane.
Hope this helps!!!
Answer:
The work done per unit kg of mass is -76.08 kJ/kg while the heat transferred per unit kg of mass is -42.01 kJ/kg.
Explanation:
For Argon the molar mass is given as
Now the gas constant for Argon is given as
Initial Temperature is T_1=10 C=10+273=283 K
Final Temperature is T_2=120 C=120+273=393 K
Initial Pressure is P_1=120 kPa
The initial volume is given as
For the polytropic process with γ=1.3 is given as
Now the volume at the second stage is given as
Now the work done per kg mass is given as
So the work done per unit kg of mass is -76.08 kJ/kg.
The heat per unit mass is given as
As the Argon gas is monotonic which gives γ_adiabatic=1.67
The heat transferred per unit kg of mass is -42.01 kJ/kg