Answer & Explanation:
//written in java
public class Main {
public static void main(String[] args) {
//declare a char variable for a, b, c
char a;
char b;
char c;
//assign a b and c
//a b and c can be replaced for with
// '#', '$', '%', then with '1', '2', '3'
// for further testing
a = 'x';
b = 'y';
c = 'z';
//output for all possible combination for a, b, c.
System.out.println("" + a + b + c + " " + a + c + b + " " + b + a + c +
" " + b + c + a + " " + c + a + b + " " + c + b + a);
}
}
A) Jason is correct because smaller wings can cut through air better.
Cast-in-place concrete beams are identified on a plan view with letters and numbers that correspond to the beam schedule.
<h3>What are concrete beams?</h3>
Concrete beams refer to a load-bearing unit that can be used to carry both horizontal and vertical loads.
Cast-in-place concrete beams are identified on a plan view with letters and numbers corresponding to the beam schedule.
Learn more about concrete beams here:
brainly.com/question/20434107
#SPJ1
It’s will be tunma if I’m correct
Answer:
work done = 665.12 kJ/k.mol of nitrogen
dQ = 685.905 kJ/k.mol of nitrogen
Explanation:
given data
pressure = 80 bar
temperature t1 = 220 K
temperature t2 = 300 K
solution
first we get here work done as considering ideal gas condition
work done = P (v2-v1 ) = nR (t2-t1)
put here value
work done = 1 × 8.314 ×( 300 - 220 )
work done = 665.12 kJ/k.mol of nitrogen
and
now we get heat transfer by 1st law of thermodynamics that is
heat transfer dQ = dv + dw
dQ = Cv dT + dw
put here value and we get
dQ = 
× (t2-t1) + 665.12
dQ = 
× (300-220) + 665.12
dQ = 685.905 kJ/k.mol of nitrogen
