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Serga [27]
3 years ago
7

PLEASE HELP AND ANSWER MY OTHER QUESTIONS!,

Engineering
1 answer:
NARA [144]3 years ago
8 0

Answer: False

Explanation:

The statement that "a person hired by a pharmaceutical company to streamline the company’s drug production process would most likely be an electrical engineer" is false.

An electrical engineer is an engineer that designs, and tests electrical equipment like smartphones, electric motors, etc. The person designs equipments which makes use of electricity or electronics.

He or she doesn't streamline the company’s drug production process, this can be the role played by the production manager.

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As resistors are added in series to a circuit, the total resistance will
olganol [36]

The equivalent of the resistance connected in the series will be Req=R₁+R₂+R₃.

<h3>
What is resistance?</h3>

Resistance is the obstruction offered whenever the current is flowing through the circuit.

So the equivalent resistance is when three resistances are connected in series. When the resistances are connected in series then the voltage is different and the current remain same in each resistance.

V eq    =    V₁    +    V₂    +    V₃

IReq    =    IR₁    +    IR₂   +    IR₃

Req    =    R₁    +    R₂   +    R₃

Therefore the equivalent of the resistance connected in the series will be Req=R₁+R₂+R₃.

To know more about resistance follow

brainly.com/question/24858512

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8 0
2 years ago
An electric motor is to be supported by four identical mounts. Each mount can be treated as a linear prevent problems due requir
Artyom0805 [142]

GIVEN:

Amplitude, A = 0.1mm

Force, F =1 N

mass of motor, m = 120 kg

operating speed, N = 720 rpm

\frac{A}{F} =  \frac{0.1\times 10^{-3}}{1} = 0.1\times 10^{-3}

Formula Used:

A = \frac{F}{\sqrt{(K_{t} - m\omega ^{2}) +(\zeta \omega ^{2})}}

Solution:

Let Stiffness be denoted by 'K' for each mounting, then for 4 mountings it is 4K

We know that:

\omega = \frac{2 \pi\times N}{60}

so,

\omega = \frac{2 \pi\times 720}{60} = 75.39 rad/s

Using the given formula:

Damping is negligible, so, \zeta = 0

\frac{A}{F} will give the tranfer function

Therefore,

\frac{A}{F} = \frac{1}{\sqrt{(4K - 120\ ^{2})}}

0.1\times 10^{-3} =  \frac{1}{\sqrt{(4K - 120\ ^{2})}}

Required stiffness coefficient, K = 173009 N/m = 173.01 N/mm

8 0
2 years ago
Where do greywater pipes generally feed into?
Mekhanik [1.2K]

Answer:

c   Waste stack

Explanation:

7 0
2 years ago
In part A you are asked to write the pseudocode for the program. In part B you are asked to write the syntax of the code for the
Naya [18.7K]

Answer:

C++.

Explanation:

#include <iostream>

#include <string>

using namespace std;

///////////////////////////////////////////////////////////////

int main() {

   string quote, book;

   int page;

   

   cout<<"What is your favorite quote from a book?"<<endl;

   getline(cin, quote);

   cout<<endl;

   /////////////////////////////////////////////

   cout<<"What book was that quote from?"<<endl;

   getline(cin, book);

   cout<<endl;

   /////////////////////////////////////////////

   cout<<"What page was that quote from?"<<endl;

   cin>>page;

   cout<<endl;

   /////////////////////////////////////////////

   int no_of_upper_characters = 0;

   for (int i=0; i<quote.length(); i++) {

       if (isupper(quote[i]))

          no_of_upper_characters++;

   }

   

   cout<<"No. of upper case characters: "<<no_of_upper_characters<<endl;

   /////////////////////////////////////////////

   int no_of_characters = quote.length();

   cout<<"No. of characters: "<<no_of_characters<<endl;

   /////////////////////////////////////////////

   bool isDog = false;

   for (int i=0; i<quote.length(); i++) {

       if (isDog == true)

           break;

       else if (quote[i] == 'd') {

           for (int j=i+1; j<quote.length(); j++) {

               if (isDog == true)

                   break;

               else if (quote[j] == 'o') {

                   for (int z=j+1; z<quote.length(); z++) {

                       if (quote[z] == 'g') {

                           isDog = true;

                           break;

                       }

                   }

               }

           }

       }

   }

   

   if (isDog == true)

       cout<<"This includes 'd' 'o' 'g' in the quote";

   //////////////////////////////////////////////

   return 0;

}

3 0
3 years ago
I need help on the Coderz Challenge missions 3 part 3. PLEASE HELP!
allsm [11]

Answer:

the answer how you analyzs the problwm

6 0
3 years ago
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