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2 years ago

Which of the following results in the release of nuclear energy?

Chemistry

2 answers:

galina1969 [7]2 years ago

8 0

Answer:

The breaking of nuclear bonds

Explanation:

The energy that comes from the breaking of nuclear bonds is what is called nuclear energy

stepladder [879]2 years ago

3 0

Answer:

C. Both the breaking of nuclear bonds and the forming of nuclear bonds.

Explanation: I took the test

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Find [H+] of a 0.056 M hydrofluoric acid solution. Ka = 1.45 x 10-7

brilliants [131]

Answer: $[H^+]$ of 0.056 M HF solution is $8.96\times 10^{-5}$

Explanation:

$HF\rightarrow H^+F^-$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.056 M and $\alpha$ = ?

$K_a=1.45\times 10^{-7}$

Putting in the values we get:

$1.45\times 10^{-7}=\frac{(0.056\times \alpha)^2}{(0.056-0.056\times \alpha)}$

$(\alpha)=0.0016$

$[H^+]=c\times \alpha$

$[H^+]=0.056\times 0.0016=8.96\times 10^{-5}$

Thus $[H^+]$ of 0.056 M HF solution is $8.96\times 10^{-5}$

8 0

2 years ago

When the oxidation number of an element decreases over the course of a reaction, that element has beenWhich of the following che

NARA [144]

AgNO3+NaCl yields AgCl+NaNo3 (reduction)
...that's the only one I know

4 0

2 years ago

What is the percent composition of calcium fluoride

vladimir1956 [14]

Answer:

78.07

Explanation:

them seperatly is

Calcium Ca 51.333%

Fluorine F 48.667%

8 0

2 years ago

While working in the chemistry lab, you dissolve 2.5g of sodium hydroxide chips into a beaker containing 50mL of water. As you p

leva [86]

Answer:

Energy was released when the sodium and hydroxide ions formed new bonds with the water.

Explanation:

4 0

2 years ago

Read 2 more answers

A solution was found to have a 15.6 % transmittance at 500 nm, its wavelength of maximum absorption, using a cell with a path le

Gnesinka [82]

For the absorbance of the solution in a 1.00 cm cell at 500 nm is mathematically given as

A’ = 0.16138

<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>

Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069

Generally, the equation for the Beer’s law is mathematically given as

A = ε*c*l

0.8069 = ε*c*(5.00 )

ε*c = 0.16138 cm-1

then for when ε*c is constant

l’ = 1.00

A’ = (0.16138 cm-1)*(1.00 cm)

A’ = 0.16138

In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is

A’ = 0.16138