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kirill [66]
3 years ago
7

How do ocean currents (specifically ocean gyres) impact climate

Chemistry
2 answers:
Alex73 [517]3 years ago
8 0

Answer:

Because ocean currents circulate water worldwide, they have a significant impact on the movement of energy and moisture between the oceans.

Explanation:

ELEN [110]3 years ago
4 0

Answer:Ocean currents and ocean gyres impact climate by circulating water worldwide with has an even bigger impact on conserving energy and helping the moisture between the oceans.

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Calculate the standard molar enthalpy of formation, in kJ/mol, of NO(g) from the following data:
Paraphin [41]

The above question is incomplete, here is the complete question:

Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:

N_2(g) + 2O_2 \rightarrow 2NO_2(g), \Delta H^o = 66.4 kJ

2NO(g) + O_2\rightarrow 2NO_2(g),\Delta H^o= -114.1 kJ

Answer:

The standard molar enthalpy of formation of NO is 90.25 kJ/mol.

Explanation:

N_2(g) + 2O_2 \rightarrow 2NO_2(g), \Delta H^o_{1} = 66.4 kJ

2NO(g) + O_2\rightarrow 2NO_2(g),\Delta H^o_{2} = -114.1 kJ

To calculate the standard molar enthalpy of formation

N_2+O_2\rightarrow 2NO(g),\Delta H^o_{3} = ?...[3]

Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

[1] - [2] = [3]

N_2+O_2\rightarrow 2NO(g),\Delta H^o_{3} = ?

\Delta H^o_{3} =\Delta H^o_{1} - \Delta H^o_{2}

\Delta H^o_{3}=66.4 kJ - [ -114.1 kJ] = 180.5 kJ

According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :

=\frac{\Delta H^o_{3}}{2 mol}

=\frac{180.5 kJ}{2 mol}=90.25 kJ/mol

3 0
3 years ago
Consider the statement: “The temperature of the land is an important factor for the ripening of oranges, because it affects the
Alexxx [7]
Physical Properties<span>: </span>Physical properties<span> can be observed or measured without changing the composition of matter. </span>Physical properties<span> are used to observe and describe matter. so physical changes are the change in temperature of the land and the evaporation of water and change humidity of the air. chemical change is the ripening of the orange</span>
7 0
3 years ago
Someone please help will mark as brainliest
wariber [46]

1. solute is the substance that is being dissolve,while solvent is dissolving medium

2.saturated is solution that contain maximum amount of solut that capable of being dissolve and supersaturated is solution that contain less amount or medium of solut that capable being dissolve : example vinger

3. is a number placed in front of a chemical symbol or formula. It shows how many atoms or molecules of the substance are involved in the reaction. For example, two molecules of hydrogen would be written as 2 H2, and two molecules of water would be written 2 H2O . yes it's can be change only in caseWhen you balance an equation you can only change the coefficients

5 0
3 years ago
PLEASE HELP ME ASAP!!!! PLEASE!!!!!!!!!! I will give brainliest and 20 points!! PLEASE!
Vika [28.1K]
#1
<span>The rate of diffusion of a gas is inversely proportional to the square root of its molecular weight. 
#2
shape, molecular weight. I don't know for sure though
#3
</span>O2, N2, Ar, H2O vapor
5 0
3 years ago
Calcium has a cubic closest packed structure (fcc) as a solid. Assuming that calcium has an atomic radius of 197 pm, calculate t
Paha777 [63]

Answer:

1.536 g/cm^3 is the density of solid calcium.

Explanation:

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

Z = number of atom in unit cell

M = atomic mass

(N_{A}) = Avogadro's number  

a = edge length of unit cell

We have:

r = 197 pm = 197\times 10^{-12} m = 197\times 10^{-12}\times 100 cm

r=197\times 10^{-10} m

a=r\times 2\sqrt{2}

a=197\times 10^{-10} m\times 2\sqrt{2}=557.200\times 10^{-10} cm

M = 40 g/mol

Z = 4

On substituting all the given values , we will get the value of 'a'.

\rho =\frac{4\times 40 g/mol}{6.022\times 10^{23} mol^{-1}\times (557.200\times 10^{-10} cm)^{3}}

\rho =1.536 g/cm^3

1.536 g/cm^3 is the density of solid calcium.

5 0
3 years ago
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