D protons. <span>the identity of an element is determined by the total number of protons present in the nucleus of an atom contained in that partial element.
._.</span>
Answer:
21.2 grams CH2Cl2
Explanation:
Number of moles: .25
Molar mass of CH2Cl2: 84.93 g/mol
Mass in grams: 84.93(0.250) = 21.2325
The balanced equation for the above reaction is as follows;
<span>Fe</span>₂<span>O</span>₃<span> + 3 CO --> 2 Fe + 3 CO</span>₂
<span>stoichiometry of CO to Fe is 3:2
molar volume states that 1 mol of any gas occupies a volume of 22.4 L
If 22.4 L contains 1 mol of CO
Then 3.65 L contains - 1/22.4 x 3.65 = 0.16 mol
3 mol of CO forms 2 mol of Fe
Then 0.16 mol of CO forms - 2/3 x 0.16 = 0.1067 mol of Fe
Therefore mass of Fe produced - 0.1067 mol x 55.8 g/mol = 5.95 g</span>
A result of the common ion effect is that the selective precipitation of a metal ion, such as Ag+, is promoted by the addition of an appropriate counter ion (X-) that produces a compound (AgX) with a very low solubility.
Answer:
3.01 L
Explanation:
V
1
: 2.75L
T
1
:
18
∘
C
V
2
: ?
T
2
:
45
∘
C
If you know your gas laws, you have to utilize a certain gas law called Charles' Law:
V
1
T
1
=
V
2
T
2
V
1
is the initial volume,
T
1
is initial temperature,
V
2
is final volume,
T
2
is final temperature.
Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.
Normally in these types of problems (gas law problems), you are given all the variables but one to solve. In this case, the full setup would look like this:
2.75
291
=
V
2
318
By cross multiplying, we have...
291
V
2
= 874.5
Dividing both sides by 291 to isolate
V
2
, we get...
V
2
= 3.005...
In my school, we learnt that we use the Kelvin value in temperature to count significant figures, so in this case, the answer should have 3 sigfigs.
Therefore,
V
2
= 3.01 L
