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2 years ago

13

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2 answers:

Svetlanka [38]2 years ago

6 0

Answer:

area of rectangle=l×b=2.4×5.8=13.92cm²

____ [38]2 years ago

4 0

The right answer is letter C

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Mrs. Blair believes there is a relationship between the number of minutes students study and their test grades. She asked her hi

kodGreya [7K]

Answer:

I would say C 80. I'm not fully sure tho.

Step-by-step explanation:

Sorry If I'm late on this or If I'm wrong

4 0

1 year ago

What is the solution to the inequality 2n+5| > 1?

hodyreva [135]

Answer:

n < - 3 or n > - 2

Step-by-step explanation:

Inequalities of the type | x | > a , have solutions of the form

x < - a or x > a

Then

2n + 5 < - 1 or 2n + 5 > 1

Solve both inequalities

2n + 5 < - 1 ( subtract 5 from both sides )

2n < - 6 ( divide both sides by 2 )

n < - 3

OR

2n + 5 > 1 ( subtract 5 from both sides )

2n > - 4 ( divide both sides by 2 )

n > - 2

Solution is n < - 3 or n > - 2

3 0

2 years ago

Plz answer for 20 pts

KATRIN_1 [288]

Answer to Problem 1: 5√3

Answer to Problem 2: 21√5

5 0

2 years ago

Read 2 more answers

I need help ASAP!!!! No links

svetoff [14.1K]

Answer:

c

Step-by-step explanation:

5 0

2 years ago

Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC

e-lub [12.9K]

Answer:

$DC=\frac{8}{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

<em>In the right triangle ABM</em>

Applying the Pythagorean Theorem

$BM^2=AB^2-AM^2$

we have

$AB=5\ units\\AM=x\ units$

substitute

$BM^2=5^2-x^2$

$BM^2=25-x^2$ -----> equation A

<em>In the right triangle BMC</em>

Applying the Pythagorean Theorem

$BM^2=BC^2-MC^2$

we have

$BC=7\ units\\MC=AC-AM=(9-x)\ units$

substitute

$BM^2=7^2-(9-x)^2$

$BM^2=49-(81-18x+x^2)$

$BM^2=49-81+18x-x^2$

$BM^2=-x^2+18x-32$ ----> equation B

equate equation A and equation B

$-x^2+18x-32=25-x^2$

solve for x

$18x=25+32\\18x=57\\\\x=\frac{57}{18}$

Simplify

$x=\frac{19}{6}$

<em>Find the length of DC</em>

$DC=AC-2x$

substitute the given values

$DC=9-2(\frac{19}{6})$

$DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units$

8 0

3 years ago