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just olya [345]
3 years ago
15

Good night. I need to go to bed. Byeeeeeeeeeeeee.​

Engineering
1 answer:
dimaraw [331]3 years ago
8 0

Answer:

BYEEEEEEEEEEEE3EEEEEEEEEE

Explanation:

dawg

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Which of the following is an example of a hardwood? A maple B spruce C pine D fir
bearhunter [10]

Answer:

A. Maple

Explanation:

Maple is a hardwood.

Hope that helps!

7 0
2 years ago
Relevance of engineering law and ethic in contemporary society​
baherus [9]

Answer:

Engineering law and ethics are the moral codes associated with the field in which engineers are meant to adhere strictly to.

These ethics help in the safety of the engineers as a result of wearing protective clothing being a part of the ethics . Accuracy should also be taken important in research and daily activities. Corrupt practices and activities which poses risk to the environment is also strictly prohibited.

7 0
4 years ago
What are the application of computer modeling in beams​
Murljashka [212]

Answer:

This paper discusses recent applications of computer modelling by the author in ... The cantilever beams were connected to a stainless steel torsion tube close to.

Explanation:The use of models in structural engineering is motivated by the work in small boxes performed by Karl … Torsional deformation of ABS beams and connection …

4 0
3 years ago
A reversible heat pump and a Carnot heat pump operate between the same two thermal reservoirs. Which heat pump has higher COP?
jonny [76]

Answer:

Both heat pump has same COP

Explanation:

Given that a reversible heat pump and a Carnot heat pump which is operating between the same temperature limits will have the same COP because the temperature limits are same, that is the source temperature and the sink temperature. Also because we know that a Carnot cycle is a totally reversible cycle. Therefore for a perfectly reversible Carnot cycle, the COP will be same for a reversible heat pump and a Carnot heat pump operating between two same thermal reservoirs.

Thus, both heat pump will have same COP.

4 0
4 years ago
An aluminum alloy tube with an outside diameter of 3.50 in. and a wall thickness of 0.30 in. is used as a 14 ft long column. Ass
slega [8]

Answer:

slenderness ratio = 147.8

buckling load = 13.62 kips

Explanation:

Given data:

outside diameter is 3.50 inc

wall thickness 0.30 inc

length of column is 14 ft

E = 10,000 ksi

moment of inertia = \frac{\pi}{64 (D_O^2 -D_i^2)}

I = \frac{\pi}{64}(3.5^2 -2.9^2) = 3.894 in^4

Area = \frac{\pi}{4} (3.5^2 -2.9^2) = 3.015 in^2

radius = \sqrt{\frac{I}{A}}

r = \sqrt{\frac{3.894}{3.015}

r = 1.136 in

slenderness ratio = \frac{L}{r}

                              = \frac{14 *12}{1.136} = 147.8

buckling load = P_cr = \frac{\pi^2 EI}}{l^2}

P_{cr} = \frac{\pi^2 *10,000*3.844}{( 14\times 12)^2}

P_{cr} = 13.62 kips

3 0
3 years ago
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