Answer:
Here's what I get
Explanation:
I don't know what the notation on page 91 is (COO⁻?), but your diagram should be something like the one below.
The stearate tails are immersed in and pointing to the centre of the green oil glob.
The negative heads are on the surface surrounded by water molecules.
You may have to draw them as COO⁻.
Answer:
2 moles of NO
Explanation:
Our reaction is:
4NH₃ + 5O₂ → 6H₂O + 4NO
4 moles of ammonia react to 5 moles of oxygen in order to produce 6 moles of water and 4 moles of NO
We need to determine the limiting reactant:
Ratio is 4:5, As 4 moles of ammonia react to 5 moles of oxygen and we have 4 moles, we definetely need 5 moles, but the problem is, we only have 2.5 moles of O₂. Oxygen is the limting reagent.
5 moles of O₂ produce 4 moles of NO, according to stoichiometry
2.5 moles of O₂ may produce (2.5 . 4) / 5 = 2 moles of NO
H₂ is the limiting reactant.
<u>Explanation:</u>
H₂ reacts with O₂
The reaction would be
2H₂ + O₂ → 2H₂O
According to the balanced equation, 2 moles of H₂ reacts with 1 mole of O₂ to form 2 moles of H₂O.
The ratio of usage of H₂ and O₂ is 2 : 1 respectively
If 3 moles of H₂ and 2 moles of O₂ are present then:
3 moles of H₂ would require 1.5 moles of O₂ ( 2 : 1 of H₂ and O₂ )
Out of 2 moles of O₂, 1.5 moles would be used and 0.5 mole would be in excess.
Therefore, H₂ is the limiting reactant as the number of moles of H₂ are not enough to use all the O₂.
Answer:
Cooffee
Explanation:
<em>the answer is coffee because coffee might be bitter</em>