69.9%
Explanation:
To find the mass percentage of iron in the compound in Fe₂O₃, we would go ahead to express the given molar mass of the iron to that of the compound.
Mass percentage =
x 100
Molar mass of Fe = 55.85g/mol
Molar mass of O = 16g/mol
Molar mass of Fe₂O₃ = 2(55.85) + 3(16) = 159.7g/mol
Mass percentage =
= 69.94% = 69.9%
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calcium,phosphorus,potassium,and sulfer
It is not equal because it dose not obey the conservation of mass. 60+25= 85 not 75.
Answer:
direct effect
Increasing the pressure increases the boiling point and decreasing the pressure decreases the boiling point