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Rudiy27
4 years ago
13

PLEASE HELP ASAP

Chemistry
1 answer:
torisob [31]4 years ago
5 0
Heredity is the study of how traits are passed from parents to offsprings through reproduction. Off springs cells acquire the genetic information from their parents. DNA bases (A,G,C,T) determine the nucleotides that will constitute the mRNA, the mRNA nucleotides determines the codons which codes for certain amino acids. The amino acids join during translation and form peptides that then join to form proteins. These proteins include enzymes that catalyses chemical reactions for example pigments of skin and hair color are produced by enzymes. Hence, proteins highly determine the traits acquired by a given organisms and therefore, variation in a gene in terms of the bases greatly affect the proteins formed hence influencing the traits of the organisms.
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Food is heated up in a microwave. The heat transfer used in a microwave is
azamat
Radiation 

hope that helped!
6 0
3 years ago
Read 2 more answers
How is iodine-131 the same as iodine-126
tamaranim1 [39]
Iodine 131 and iodine 126 are the same in the sense that, they both have the same number of electrons and protons in their atoms, it is only the number of their neutrons that is different. Iodine 131 has 78 neutrons while iodine 126 has 73 neutrons.
8 0
3 years ago
2.
katovenus [111]

Answer:

A. 6atm

Explanation:

Using pressure law equation:

P1/T1 = P2/T2

Where;

P1 = initial pressure (atm)

T1 = initial temperature (K)

P2 = final pressure (atm)

T2 = final temperature (K)

According to this question;

P1 = 3 atm

P2 = ?

T1 = 120K

T2 = 240K

Using P1/T1 = P2/T2

3/120 = P2/240

Cross multiply

240 × 3 = P2 × 120

720 = 120P2

P2 = 720/120

P2 = 6atm

4 0
3 years ago
Calculate the volume of a 0.323-mol sample of a gas at 265 K and<br> 0.900 atm.
Katarina [22]

Answer:

V = 7.8 L

Explanation:

Message

5 0
4 years ago
Compound a is an alkene that was treated with ozone (followed by dms) to yield only 4-heptanone. Draw the major product that is
olga nikolaevna [1]

Alkenes on reacting with ozone results in the formation of ozonide which undergo reductive  cleavage in presence of dimethyl sulfide to form carbonyl compounds (aldehyde or ketone). Whereas in presence of hydrogen peroxide it undergoes oxidative cleavage to form carboxylic acids or ketones.

Since, A alkene yields 4-heptanone only on treatment with ozone and DMS thus, it implies that both the chains on the side of the double-bond are similar the product is 4-heptanone that means the double bond is present between the chains at the 4th carbon. Therefore the structure of compound A is 4,5-dipropyloct-4-ene.

The reaction is as shown in the image.

The reaction of A with m-CPBA (meta-perchlorobenzoic acid) followed by aqueous acid H_3O^{+} is shown in the image.

m-CPBA (meta-perchlorobenzoic acid) is a peracid and forms epoxides on reacting with alkenes.

5 0
3 years ago
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