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IceJOKER [234]
3 years ago
12

Write an equation in slope-intercept form.

Mathematics
1 answer:
podryga [215]3 years ago
8 0

Given:

The table of values.

To find:

The equation in slope intercept form.

Solution:

From the given table it is clear that the line passes through the points (5,17), (8,41) and (12,73).

Consider any two points from the table, i.e., (5,17) and (8,41). So, the equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-17=\dfrac{41-17}{8-5}(x-5)

y-17=\dfrac{24}{3}(x-5)

y-17=8(x-5)

y=8x-40+17

y=8x-23

Therefore, the equation of line in slope intercept form is y=8x-23.

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It's A. segment A"B" is closer to segment C than segment A"B".

Step-by-step explanation:

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3 years ago
I need the steps and answers pleass
Schach [20]

Answer:

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5 0
2 years ago
Please answer both with work,please use a paper and picture, thanks ​
Irina-Kira [14]

Answer:

a.  $ \frac{\textbf{17}}{\textbf{4}} $

b.  $ \frac{\textbf{3}}{\textbf{8}} $

Step-by-step explanation:

a. $ \textbf{3} \hspace{1mm} \textbf{+} \hspace{1mm} \textbf{1}\frac{\textbf{1}}{\textbf{4}} $

A mixed fraction of the form $ a\frac{x}{y} = a + \frac{x}{y} $

$ \therefore 3 + 1\frac{1}{4} = 3 + 1 + \frac{1}{4} $

$ = 4 + \frac{1}{4} $

$ = \frac{\textbf{17}}{\textbf{4}} $

b. $ \textbf{2} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{1}\frac{\textbf{5}}{\textbf{8}} $

A mixed fraction of the form $ -c\frac{a}{b} = - c - \frac{a}{b} $

$ \therefore 2 - 1\frac{5}{8} = 2 - 1 - \frac{5}{8} $

$ = 1 - \frac{5}{8} $

$ = \frac{8 - 5}{8} $

$ = \frac{\textbf{3}}{\textbf{8}} $

Hence, the answer.

8 0
3 years ago
The tree diagram represents an experiment consisting two trials
zavuch27 [327]

Answer:

0.35

Explanation:

  • P ( B and D )
  • 0.5 * 0.7
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<u>Follow the branch B and then branch D</u>

  • multiply both the selected probabilities to calculate total probability.

6 0
2 years ago
Read 2 more answers
How do you write range on a graph?
Ratling [72]

The range of a function is the set of all possible outputs.

When the quadratic functions are in standard form, they generally look like this:

f(x) = ax^{2}  + bx + c

If a is positive, the function opens up; if it’s negative, the function opens down. In this form, the y-coordinate of the vertex is found by evaluating f(−\frac{b}{2a}). For example, consider this function:

f(x) = -2x^{2} + 8x -3\\

So we’re gonna do: −b/2a=−8/2(−2)=−8/−4=2

Then, we plug this in:

f(2) = -2(2)^{2} +8(2) -3 = 5

a is negative, so the range is all real numbers less than or equal to 5.

Learn more about range at

brainly.com/question/2264373

#SPJ4

4 0
1 year ago
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