Whenever there is a change in velocity, either due to a change in speed or a change in direction, there will be non-zero acceleration. ... Acceleration is not constant if the net force is not constant.
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Answer:I'm not sure, but I think it's antisocial
Explanation:
Answer:
Explanation:
Here image distance is fixed .
In the first case if v be image distance
1 / v - 1 / -25 = 1 / .05
1 / v = 1 / .05 - 1 / 25
= 20 - .04 = 19.96
v = .0501 m = 5.01 cm
In the second case
u = 4 ,
1 / v - 1 / - 4 = 1 / .05
1 / v = 20 - 1 / 4 = 19.75
v = .0506 = 5.06 cm
So lens must be moved forward by 5.06 - 5.01 = .05 cm ( away from film )
At the boundary between air and glass, we can see mainly refraction ...
the path of the light bends as it crosses the boundary, and proceeds
from there in a different direction.
If we're very careful and make sensitive measurements, then we can also
detect transmission, some reflection, and a tiny bit of dispersion at the boundary.
Answer:
The electric force on q₁ is .
Explanation:
Given that,
Charge on
Distance
Charge on at origin
Distance
Charge on
We need to calculate the electric force on q₁
Using formula of electric force
Put the value into the formula
Negative sign shows the attraction force.
We need to calculate the electric force F₁₃
Positive sign shows the repulsive force.
We need to calculate the net electric force
Hence, The electric force on q₁ is .