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dalvyx [7]
3 years ago
6

According to the law of conservation of mass, if five atoms of hydrogen are used

Chemistry
1 answer:
Zanzabum3 years ago
5 0

Answer:

the law of conservation says the product side will have 5 hydrogen, unless a coefficient is added.

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What is Delta.Gsystem for the system that is described by the following data? Delta.Hsystem = –345 kJ, T = 293 K, Delta.Ssystem
ryzh [129]

Answer:

-209 kJ

Explanation:

I did the math. You're welcome ;)

6 0
3 years ago
Which processes must happen for sand to eventually become metamorphic rock? In one to two sentences, name and briefly describe t
trapecia [35]

Answer:

Sand may be deposited as sediments that become sedimentary rocks after hardening, or lithifying. Extreme burial pressure, rising temperature at depth, and a lot of time, will transform just about any rock to become a metamorphic rock.

Explanation:

4 0
3 years ago
Which molecule has a dipole moment of 0 d?
fiasKO [112]
The answer is 

a symmetrical molecule.


5 0
3 years ago
A fluorine atom has 9 positive charge,9 negative charges and a mass of 19. Describe the structure of its atom.
Tanya [424]
The atomic structure of the atom contains 9 positively charged particles (protons) and 10 neutrally charged particles (neutrons) in the center of the atom in a clump called the nucleus. Those 9 negatively charged particles (electrons) are moving around outside of the nucleus.
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To calculate the number of neutral charges, subtract the positive charges from the mass (19 - 9), and you get the number of neutral charges (10).


6 0
3 years ago
A buffer contains 0.18 mol of propionic acid (C2H5COOH) and 0.26 mol of sodium propionate (C2H5COONa) in 1.20 L. What is the pH
Yuki888 [10]

Answer:

1) pH = 5.05

2) pH = 5.13

3) pH = 4.97

Explanation:

Step 1: Data given

Number of moles of propionic acid = 0.18 moles

Number of moles sodium propionate = 0.26 moles

Volume = 1.20 L

Ka = 1.3 * 10^-5    → pKa = 4.989

Step 2: Calculate concentrations

Concentration = moles / volume

[acid]= 0.18/ 1.2 =0.150 M

[salt]= 0.26/ 1.3 = 0.217 M

pH = 4.89 + log(0.217/0.150)=<u>5.05</u>

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What is the pH of the buffer after the addition of 0.02 mol of NaOH?

moles acid = 0.18 - 0.02 = 0.16

[acid]= 0.16/ 1.2=0.133 M

moles salt = 0.26 + 0.02 = 0.28

[salt]= 0.28/ 12=0.233

pH = 4.89 + log 0.233/ 0.133 = 5.13

What is the pH of the buffer after the addition of 0.02 mol of HI?

moles acid = 0.18+ 0.02 = 0.20 moles

[acid]= 0.20/ 1.2 = 0.167 M

[salt]= 0.26 - 0.02= 0.24 moles

[salt]= 0.24/ 1.2 = 0.20 M

pH = 4.89 + log 0.20/ 0.167= 4.97

8 0
3 years ago
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