For all question, all you need to use is the mole-mole ratio.
a) 25 moles C2H6O (3 moles O2/ 1 mol C2H6O)= 75 moles O2
b) 30 moles O2 (1 moles C2H6O/ 3 moles O2)= 10 moles C2H6O
c) 23 moles CO2 (3 moles O2/ 2 moles CO2) = 34.5 moles O2
d) 41 moles H2O ( 1 moles C2H6O/ 3 moles H2O= 13.7 moles C2H6O
Answer:
P2 = P1*n2 / n1
=1.02 atm *0.008 moles / 0.00113 moles
= 7.22 atm
∴the new pressure will be 7.22 atm
Explanation:
Single-celled organisms<span> which use asexual reproduction can </span>do<span> so very rapidly simply by </span>dividing<span> into two equal halves. This is called binary fission. In yeasts the </span>cell<span> does not </span>divide<span> equally in two halves; instead, there is a large mother </span>cell<span> and a smaller daughter </span>cell<span>. This is called budding.</span>
2 Na + 2 H2O → 2 NaOH + H2 (balanced equation)
The answer would be 2, since 2 in the coefficient of both Na and NaOH