a ball is thrown horizontally from a 20 m high building with a speed of 5.0 m/s. How far from the base of the building does the
ball hit the ground?
1 answer:
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To solve this problem we will apply the concepts related to energy conservation, so the potential energy in the package must be equivalent to its kinetic energy. From there we will find the speed of the package in the vertical component. The horizontal component is given, as it is the same as the one the plane is traveling to. Vectorially we will end up finding its magnitude. So,
Here,
m = Mass
g = Gravity
h = Height
v = Velocity
Rearranging to find the velocity
Replacing,
Using the vector properties the magnitude of the velocity vector would be given by,
Therefore the package is moving to 66.2m/s