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Naily [24]
3 years ago
9

During an eclipse the sun the earth and the moon act as a light source,an obstacle or screen=

Physics
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer:

Un eclipse solar se produce cuando la luna se interpone en el camino de la luz del sol y proyecta su sombra en la Tierra. Eso significa que durante el día, la luna se mueve por delante del sol y se pone oscuro. ... Este eclipse total se produce aproximadamente cada año y medio en algún lugar de la Tierra.

Explanation:

espero que te

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Each part of the spectrum has a different range of wavelengths (which correspond to frequency, color, and energy) at which you can find it.

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What makes conductors conductors?
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"Conductor" implies that the outer electrons of the atoms are loosely bound and free to move through the material.

Explanation:

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A toroid has a square cross section with the length of an edge equal to the radius of the inner surface. The ratio of the magnit
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The voltage or potential difference provides the ____ required for electrons to travel through a circuit
galben [10]

Answer:

a. push

Explanation:

Voltage is the force or pressure that is responsible for pushing the charge or electrons to flow in a closed-looped electrical circuit. This flow of electrons (charge) is called the electric current. It is also defined as the difference in electric potential per unit charge between two points in an electric field.

5 0
3 years ago
Estimate the Joule-Thomson coefficient of refrigerant-134a at 0.70 MPa and 50°C. Assume the second state will be selected for a
leva [86]

Answer:

\mu = 0.018\,\frac{^{\textdegree}C}{kPa}

Explanation:

The Joule-Thomson coefficient is the ratio of the change of temperature to the change of pressure under isoenthalpic conditions:

\mu = \left(\frac{\Delta T}{\Delta P}\right)_{h}

Initial and final properties are:

T_{1} = 50^{\textdegree}C, P_{1}=700\,kPa, h_{1}=288.54\,\frac{kJ}{kg}. Superheated Vapor.

T_{2} = 48.186^{\textdegree}C, P_{2}=600\,kPa, h_{2}=288.54\,\frac{kJ}{kg}. Superheated Vapor.

The Joule-Thomson coefficient is approximately:

\mu = \frac{50^{\textdegree}C-48.186^{\textdegree}C}{700\,kPa-600\,kPa}

\mu = 0.018\,\frac{^{\textdegree}C}{kPa}

5 0
4 years ago
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