Answer:
1.42 s
Explanation:
The equation for free fall of an object starting from rest is generally written as
where
s is the vertical distance covered
a is the acceleration due to gravity
t is the time
On this celestial body, the equation is
this means that
so the acceleration of gravity on the body is
The velocity of an object in free fall starting from rest is given by
In this case,
g = 20.08 m/s^2
So the time taken to reach a velocity of
v = 28.6 m/s
is
Answer:
b) Vectors A and B are in the same direction.
Explanation:
To understand this problem we will say that vector A has a magnitude of 5 units and vector B a magnitude of 3 units. In the subtraction of vectors the initial parts of vectors always bind together. And the vector resulting from the subtraction is traced from the end of the second vector (B) to the end of the first vector (A).
The length of the resultant vector will be 5 - 3 = 2
In the attached image, we analyze case a), b), and d)
For a)
As we can see in the attached image the resultant vector has a length of 8 units.
For d)
As we can see in the attached image the resultant vector has a length of 5.83 units.
For b)
The resultant vector has a length of 2 units.
Therefore the case given in b) is true
