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NemiM [27]
3 years ago
6

The side lengths of a square are each 4p. By adding 3 to the length and subtracting 3 from the width, a rectangle is made. What

is the area of the rectangle?
Mathematics
1 answer:
AysviL [449]3 years ago
3 0

Answer:

area will be

16p {}^{2}  - 9

Step-by-step explanation:

after addition of 3, the length will be =》(4p+3)

after subtracting 3, the width will be =》(4p-3)

area = length × width

  • (4p+3) (4p-3)
  • 16p^2 - 9

the area will be

16p {}^{2}   - 9

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em>

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A recipie calls for 2 2/4 cups of raisins, but julie only has a 1/4 cup measuring cup. How many 1/4 cups does julie need to meas
scZoUnD [109]

Answer:

10 cups

Step-by-step explanation:

1/4 cup times 4 is 1 cup

1/4 cup times 8 is 2 cups

now you have your two cups and you need two more 1/4 to make 2/4

3 0
3 years ago
Is there a relationship between the area and the perimeter of a rectangle
maksim [4K]
Well, an area and perimeter have formula's. The formula of area is length times width. The formula of perimeter is to basically length plus length plus width plus width. For instance, let's say the rectangles width is 5 and length is 6. So you do 5 plus 5 which is 10 and then 6 plus 6 which is 12. And then, 12 plus 10 equals 22. So the perimeter would be 22. If you were to find the area, you would do 6 times 5 and the area would be 30.
I hope this helps :)
3 0
3 years ago
El resultado de la adición 1/3 + 1/9 es =?
murzikaleks [220]

Answer:

4/9

Step-by-step explanation:

You're welcome i worked it out on a piece of paper

5 0
3 years ago
A solution is heated from 0°C to 100°C. Between 0°C and 50°C, the rate of temperature increase is 1.5°C/min. Between 50°C and 10
muminat

Answer:

0.6 °C/min

Step-by-step explanation:

The relationship between rates and movement is ...

time = distance/speed

Here, the "distance" is measured in °C, and the "speed" is the rate of change of temperature.

For the first half of the heating, the time required is ...

(50°C -0°C)/(1.5 °C/min) = 50/(3/2) min = 100/3 min

For the second half of the heating, the time required is ...

(100°C -50°C)/(4/10 °C/min) = 50/(4/10) = 125 min

Then the total time is ...

((100/3) +125) min = (475/3) min

And the average rate of temperature increase is ...

total temperature change / total time

= (100°C -0°C)/(475/3 min) = 300/475 °C/min = 12/19 °C/min ≈ 0.6 °C/min

4 0
3 years ago
Find the percent if the common ratio is 0.29
Tasya [4]
The percent would be 29%. You need to move the decimal to the right twice.
8 0
3 years ago
Read 2 more answers
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