The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g
<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
- Volume = 250 mL = 250 / 1000 = 0.25 L
- Molarity = 0.3 M
Mole = Molarity x Volume
Mole of Na₂SO₄ = 0.3 × 0.25
Mole of Na₂SO₄ = 0.075 mole
<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
- Molar mass of Na₂SO₄ = 142.05 g/mol
- Mole of Na₂SO₄ = 0.075 mole
Mass = mole × molar mass
Mass of Na₂SO₄ = 0.075 × 142.05
Mass of Na₂SO₄ = 10.65 g
Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.
Learn more about molarity:
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KE = 1/2 * m * v^2
KE = 1/2 * 130 * 23^2
KE = 34385J
I think it’s A but, don’t come at me if I’m wrong. Btw I read over it multiple times so this isn’t a random guess. Good luck tell me if you got it right
Answer: (g) - gas, (l) - liquid and (aq) - aqueous solution.
Explanation: The reactants are written in terms of their chemical formula on the left hand side of the arrow and the products are written in terms of their chemical formula on right hand side of the arrow.
The chemical symbols are followed by their physical states such as (l) for liquid, (s) for solid, (g) for gas and (aq) for aqueous.
Gold is Au on the periodic table
