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3 years ago

Color blindness is a sex-linked, _______ trait.

Chemistry

2 answers:

lidiya [134]3 years ago

5 0

Answer:

recessive trait

galina1969 [7]3 years ago

5 0

Answer:

recessive

Explanation:

Color blindness is a sex-linked, <u>recessive</u> trait.

hope this helps and is right :)

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You are given an unknown type of clothing dye. How could you use the procedures in this lab to see if this dye is a mixture? Ple

Sergeeva-Olga [200]

To find out if a dye is a mixture or not, you can make use of the chromatography method of separation.
If the dye is a mixture, the different elements inside the mixture will be separated out during chromatography and they will form different bands on the cinematographic paper but if the dye is composed of only one element, only one band will be formed on the cinematographic paper.

3 0

3 years ago

Consider the reaction: 2 SO2(g)+O2(g)→2 SO3(g) If 285.5 mL of SO2 reacts with 158.9 mL of O2 (both measured at 315 K and 50.0 mm

Tanzania [10]

Answer:

a. Oxygen is the limiting reagent. $n_{SO_3}^{Theoretical}=8.096x10^{-4}mol SO_3$

b. $Y=58.9$ %

Explanation:

Hello,

a. Limiting reagent and sulfur trioxide's theoretical yield.

At first, we must compute the involved moles for both sulfur dioxide's and oxygen's as follows, considering the volumes in liters and the pressure in atm of 50.0mmHg*1atm/760mmHg=0.0658atm:

$n_{SO_2}=\frac{PV}{RT}=\frac{0.0658atm*0.2855L}{0.082\frac{atm*L}{mol*K}*315K} =7.273x10^{-3}molSO_2 \\n_{O_2}=\frac{PV}{RT}=\frac{0.0658atm*0.1589L}{0.082\frac{atm*L}{mol*K}*315K} =4.048x10^{-4}molO_2$

Afterwards, by considering the properly balanced chemical reaction:

$2SO_2(g)+O_2(g)-->2SO_3$

We compute the oxygen's moles that completely reacts with the previously computed $7.273x10^{-3}$ moles of $SO_2$ as follows:

$7.273x10^{-3}molSO_2*\frac{1molO_2}{2molSO_2} =3.6365x10^{-3}molO_2$

That result let us know that the oxygen is the limiting reagent since just $4.048x10^{-4}$ moles are available in comparison with the $3.6365x10^{-3}$ moles that completely would react with $7.273x10^{-3}$ moles of $SO_2$ .

Now, to compute the theoretical yield of sulfur trioxide, we apply the following stoichiometric relationship:

$n_{SO_3}^{Theoretical}=4.048x10^{-4}molO_2*\frac{2molSO_3}{1molO_2} =8.096x10^{-4}mol SO_3$

b. Percent yield.

At first, we must compute the collected (real) moles of sulfur trioxide:

$n_{SO_3}^{real}=\frac{PV}{RT}=\frac{0.0658atm*0.1872L}{0.082\frac{atm*L}{mol*K}*315K} =4.769x10^{-4}molSO_3$

Finally, we compute the percent yield:

$Y=\frac{n_{SO_3}^{real}}{n_{SO_3}^{Theoretical}} *100$ %

$Y=\frac{4.769x10^{-4}mol SO_3}{8.096x10^{-4}mol SO_3} *100$ %

$Y=58.9$ %

Best regards.

7 0

3 years ago

Read 2 more answers

(Science DUE 6:30 AM!!)

Blababa [14]

The answer: Periods form horizontal rows, groups form vertical columns

Explanation:
The horizontal rows on the periodic table are called periods, while the verticals columns are called groups. Elements that are in the same group have similar properties. For example Group 1 is called the alkali metals. These are all soft, reactive metals.

4 0

4 years ago

In one form of beta decay potassium decays to produce calcium. What values do the letters represent

LenKa [72]

Answer:

A. 19

B. 40

C. - 1

Explanation: Please see attachment for explanation