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3 years ago

11

How does Newton's second law apply to an "Egg Drop" experiment?

1 answer:

Black_prince [1.1K]3 years ago

6 0

Because an object in rest stays in rest until an unequal force pushes it so gravity is pushing on the egg making it drop

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When a beam of charged particles moves through a magnetic field, what is the evidence that particles in the beam have momentum g

Vsevolod [243]

The charged particles are often deflated in a magnetic field.

<h3>What is a magnetic field?</h3>

The term charge refers to a positive or negative entity. The can be created when a charge is made to pass through a conductor in a magnetic field.

A magnetic field is created when we have a north pole and a south pole. The charged particles could be made to pass through the electric field and when that happens, we can see a pattern a shown in the image attached.

Thus, we can see that the charged particles are often deflated in a magnetic field.

Learn more about magnetic field:brainly.com/question/23096032

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1 year ago

How does climate change?

Korvikt [17]

Answer:

Con el cielo del agua

Explanation:

espero que te ayude

5 0

2 years ago

Read 2 more answers

Which planet is smaller than Earth’s core?

makvit [3.9K]

Answer:

The answer <em><u>is C. Mars</u></em>. Mars and Mercury are both smaller than Earth's core. Hope this helps you :)

7 0

3 years ago

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Bob, Jill, Kim, and Steve measure an object's length, density, mass, and brightness, respectively. Which student must derive a u

netineya [11]

The answer is A. Bob (<span>object's length)

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3 years ago

The gravitational force of a star on an orbiting planet 1 is f1. planet 2, which is three times as massive as planet 1 and orbit

vovikov84 [41]

Gravitational force is given by, $F= G\frac{mM}{R^{2}}$

Where, m and M are the masses of the objects, R is the distance between them and G gravitational constant.

Gravitational force of the star on planet 1, $F_{1}= G\frac{m_{1}M}{R^{2}}$

Gravitational force of the star on planet 2, $F_{2}= G\frac{3m_{1}M}{(3R)^{2}}$

Ratio, $\frac{F_{1}}{F_{2}}= \frac{\frac{Gm_{1}M}{R^{2}}}{\frac{G3m_{1}M}{(3R)^{2}}}$

$\frac{F_{1}}{F_{2}}= \frac{3}{1}$

Therefore, the gravitational force of the star on the planet 1 is three times that on planet 2.

6 0

3 years ago

Read 2 more answers