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V125BC [204]
3 years ago
11

How does Newton's second law apply to an "Egg Drop" experiment?

Physics
1 answer:
Black_prince [1.1K]3 years ago
6 0
Because an object in rest stays in rest until an unequal force pushes it so gravity is pushing on the egg making it drop
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where would the spaceprobe experience the strongest net (or total) gravitional force exerted on it by Earth and Mars
Arte-miy333 [17]

Answer:

r = 41.1 10⁹ m

Explanation:

For this exercise we use the equilibrium condition, that is, we look for the point where the forces are equal  

                  ∑ F = 0

                  F (Earth- probe) - F (Mars- probe) = 0

                  F (Earth- probe) = F (Mars- probe)

Let's use the equation of universal grace, let's measure the distance from the earth, to have a reference system

the distance from Earth to the probe is        R (Earth-probe) = r

the distance from Mars to the probe is        R (Mars -probe) = D - r

where D is the distance between Earth and Mars

                   

                 G  \ \frac{m \ M_{Earth}}{r^2} = G  \ \frac{m \ M_{Mars}}{(D-r)^2}

                 M_earth (D-r)² = M_Mars r²

                 (D-r) = \sqrt{ \frac{M_{Mars}}{ M_{Earth}} }    r

                  r ( 1 + \sqrt{ \frac{M_{Mars}}{M_{Earth}} }) = D

                  r = \frac{D}{ 1+ \sqrt{\frac{M_{Mars}}{ M_{Earth}} } }

We look for the values ​​in tables

                  D = 54.6 10⁹ m (minimum)

                  M_earth = 5.98 10²⁴ kg

                  M_Marte = 6.42 10²³ kg = 0.642 10²⁴ kg

                   

let's calculate

                  r = 54.6 10⁹ / (1 + √(0.642/5.98)  )

                  r = 41.1 10⁹ m

5 0
3 years ago
Pepe and Alfredo are resting on an offshore raft after a swim. They estimate that 3.0 m separates a trough and an adjacent crest
Agata [3.3K]

Answer:

The velocity (v) of the wave is 3.08 ms^{-1}.

Explanation:

According to the figure, the distance (\large{L}) between a trough and its adjacent crest is \large{L = 3 m}. Also the wavelength (\large{\lambda}) of the wave is \large{\lambda = 2L}. Pepe and Alfredo count 11 crests to pass the raft in \large{t} = 21.5 s.

So, the time period (\large{T}) of oscillation of the wave is

\large{T} = \dfrac{t}{11} = \dfrac{21.5}{11} = 1.95s

So, the velocity (\large{V}) of the wave is

\large{V = \dfrac{\lambda}{T} = \dfrac{2 \times L}{T} = \dfrac{2 \times 3}{1.95}= 3.08 ms^{-1}}

4 0
3 years ago
A tow truck exerts a force of 3000 n on a car, accelerating it at 2 meters per second per second. what is the mass of the car?
Artemon [7]
If the force is 3,000 N and the acceleration is 2 m/s/s. The mass of the car is 1,500 grams (or whatever unit of mass or weight is used in the answer- pounds, kilograms e.t.c.).
6 0
3 years ago
Which country features the largest scale model of the solar system?.
matrenka [14]

The Sweden

___________

8 0
2 years ago
Read 2 more answers
A bodybuilder loads a bar with 550 Newtons (~125 pounds) of weight and pushes the bar over her head 10 times. Each time she lift
mafiozo [28]

Work = (force) x (distance)

Each time she lifts the weight, she does

          (550 N) x (0.5 m) = 275 joules of work against gravity.

Each time she lets the bar down gently, gravity does

          (550 N) x (0.5 m) = 275 joules of work against her muscles. 

If the human physical muscular system were 100% efficient, and capable
of absorbing work as well as spending it, then the bodybuilder would do
exactly zero work in the process of 1-up followed by 1-down.


3 0
3 years ago
Read 2 more answers
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