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2 years ago

During 30.0 s, a train was moving with constant speed of 72 km/h. How far away it could relocate within this time?

Physics

1 answer:

bazaltina [42]2 years ago

7 0

Answer:

the distance is 0.6 km

Explanation:

The computation of the distance is shown below:

As we know that

Distance = Speed × time

where

Speed = 72 km/h

And, the time is 30 seconds

So, the distance is

= 72 × 30

= 0.6 km

Hence, the distance is 0.6 km

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3 years ago

Una pelota de tenis de 100 g de masa lleva una rapidez de 20 m/s. Al ser golpeada por una raqueta, se mueve en sentido contrario

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Answer:

Explanation:

El impulso aplicado a la pelota produce una variación en su momento lineal.

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2 years ago

An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the

poizon [28]

Answer:

The value is $A = 0.014 \ m$

Explanation:

From the question we are told that

The mass of the object is $m = 2.0 \ kg$

The unstressed length of the string is $l = 0.08 \ m$

The length of the spring when it is at equilibrium is $l_e = 5.9 \ cm = 0.059 \ m$

The initial speed (maximum speed)of the spring when given a downward blow $v = 0.30 \ m/s$

Generally the maximum speed of the spring is mathematically represented as

$u = A * w$

Here A is maximum height above the floor (i.e the maximum amplitude)

and $w$ is the angular frequency which is mathematically represented as

$w = \sqrt{\frac{k}{m} }$

$u = A * \sqrt{\frac{k}{m} }$

=> $A = u * \sqrt{\frac{m}{k} }$

Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

$b = l -l_e$