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pav-90 [236]
3 years ago
12

The correlation between the amount of carbon dioxide and the plants growing is, as the plants are growing the carbon dioxide lev

el
(increasing/decreasing)​
Chemistry
1 answer:
Kitty [74]3 years ago
8 0

Answer:

Decreases

Explanation:

As plants take out carbon dioxide from the atmosphere which they use for photosynthesis (making food). So as the number of plants increases carbon dioxide in the air decreases.

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What criteria are used to classify matter?
Naily [24]
Anything that occupies space and has mass.
6 0
3 years ago
Air in a 0.3 m3 cylinder is initially at a pressure of 10 bar and a temperature of 330K. The cylinder is to be emptied by openin
sergiy2304 [10]

Answer:

(a) Temperature = 330 K, and mass = 0.321 kg

(b) T₂ = 171.56 K, mass = 0.32223 kg

Explanation:

For a constant temperature process we have

p₁v₁ = p₂v₂

Where p₁ = initial pressure = 10 bar = 1000000 Pa

p₂ = final pressure = 1 atm = 101325 Pa

v₁ initial volume = 0.3 m³

v₂ = final volume = unknown

From the relation we have v₂ = 2.96 m³

Therefore at constant temperature 2.93 m³ - 0.3 m³ or 2.66 m³ will be expelled from the container

Temperature = 330 K, and mass =

Also from the relation p1v1 = mRT1

We have, (1000000×0.3)/(8314×330) = 109..337 mole

For air mass

Mass = 3.171 kg

After opening we have

p2v2/(RT1) = n2 = 11.07 mol or 0.321 kg

or

(b) This is said to be adiabatic condition hence

Here

But cp = 29 (J/mol K).

and p₁v₁ = RT₁ therefore R = 1000000*0.3/330 = 909.1 J/mol·K

And For perfect gas γ = 1.4

Hence T₂ = 171.56 K

γ =cp/cv therefore cv=cp/γ = 29/1.4 = 20.714 (J/mol K). and R =cp-cv = 8.29 J/mol·K

Therefore p1v1/(RT1) = 109.66 moles and we have

p2v2/(R×T2) = 11.11 mole left

For air that is 0.32223 kg

5 0
4 years ago
As the temperature of a medium increases, the speed of the sound wave
Irina-Kira [14]

Answer : As the temperature of a medium increases, the speed of the sound wave increases because the particles bump into each other more often.  

Explanation :

The dependency of the speed of the sound wave and the temperature of the medium is :

v=\sqrt{\gamma\ R\ T}

Where

\gamma = ratio of specific heat

R is gas constant

T is the temperature

The speed of the wave is directly proportional to the temperature. As the temperature of a medium increase, the speed of the sound increase. The particles start vibrating faster. Hence, they bump into each other.

Hence, the correct option is (A).

8 0
3 years ago
Read 2 more answers
What are the products formed when ethane burns in excess oxygen?
Neporo4naja [7]
2 C2H6 + 7 O2 -> 4CO2 + 6 H2O 
<span>so the products are carbondioxide & water vapour</span>
3 0
3 years ago
Fill in the [?]:<br> 3,721 nm = [?]m<br> Give your answer in standard form.
swat32

0.000003721

...........................

...........................

4 0
3 years ago
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