Answer:
K = 2.7x10⁻⁵ at 25ºC
Explanation:
A way to write Arrhenius equation is:
ln K = - Ea/R × (1/T) + lnA
If you graph ln K as Y and 1/T as X (Absolute temperature in K), the equation you will obtain is:
Y = -13815X +35.817
R² = 0.9927
(Taking the last k point as 0.0386) (ln 0.0386), <em>0.1386 has no sense</em>)
Your slope is -13815
-13815K = - Ea/R
-13815K×8.314J/molK = 114858J/mol = Ea
And your intercept =
lnA = 35.817
A = 3.59x10¹⁵
Now, you want to know rate constant at 25ºC = 298.15K. Replacing in the equation (Where Y is ln (activation energy) and X is 1/T):
Y = -13815X +35.817
Y = -13815(1/298.15K) +35.817
Y = -10.5187
lnK = -10.5187
<h3>K = 2.7x10⁻⁵ at 25ºC</h3>
Answer:
Its phosphorus (P)
Explanation:
In writing the electron configuration for Phosphorus the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for Phosphorous go in the 2s orbital. The next six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s. Since the 3s if now full we'll move to the 3p where we'll place the remaining three electrons. Therefore the Phosphorus electron configuration will be 1s22s22p63s23p3.
Carbon dioxide and oxigen
Answer:
It would take less time, because having a lower temperature of latent heat means that at a lower temperature it merges, therefore the closer it will be to the temperature of solification which is 0 degrees Celsius or Celsius ... It is then that it would solidify in less time than water
Explanation:
By acting and having all the same properties as water except for latent heat, it considers that the solidification temperature is 0 degrees Celsius like water.
Molarity is measured in moles per Liter. If there are 1.35 g/mL, find out how many grams there are in a liter of solution.
If there are 1000 mL in one liter, we can multiply by 1000 to get g/L
1.35 g/mL x 1 Liter/1000 mL = 1350 g per Liter of solution
By weight, the NaOH is 33% or .33
1350 g x .33 = 445.5 g of NaOH
Molar mass of NaOH is 39.997 g
445.5 g x 1 mol NaOH/39.997 g = 11.13833538 moles per Liter
Rounded to significant figures, the answer is 11 mol/L NaOH
