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alekssr [168]
3 years ago
5

When 100ml of M HCl is mixed with 100ml of N NaOH, the pH of the resulting solution is

Chemistry
1 answer:
RoseWind [281]3 years ago
4 0

Answer:

Option d. 7

Explanation:

A mixture of a strong base and a strong acid produce a neutral salt and water.

This is the reaction of neutralization:

HCl + NaOH → NaCl + H₂O

NaCl →  Na⁺  +  Cl⁻

Sodium chloride is neutral salt which does not give H⁻ neither OH⁻ to medium, that's why pH is neutral.

Both ions are derivated from a strong acid and base so they do not make hydrolisis. They are a conjugate pair of a weak acid and base. The reactions can not occur:

Cl⁻  +  H₂O ← OH⁻  +  HCl

Na⁺  +  H₃O⁺ ← NaOH  + H₂O

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Which of the following is a characteristic of a good roasting pan? ​
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What was John Dalton's contribution to the development of the atomic theory?
Lorico [155]

John Dalton made some hypothesis about the structure of atom. He proposed that matter is composed of great number of indivisible particles called atoms they can neither be destroyed nor be created.

<h3>What is atomic theory?</h3>

There are different theories regarding the structure and electronic properties of an atom. Many scientists contributed to the modern theory of atomic structure in which John Dalton was first to mention the word atom.

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6 0
1 year ago
8moles of Na2Cr2O2 is how much mass​
Margaret [11]

\boxed{\boxed{\mathfrak{ 1\: mole \:of \:Na_2Cr_2O_2\: = \:it's \:Gram\: Mol. \: mass}} }

\underline{ \mathfrak{ Gram \:molecular \:mass \:of \: \red{ Na_2Cr_2O_2}}}

= 2 × 23 + 2 × 52 + 2 × 16

= 182 grams

1 mole of Na_2Cr_2O_2 weighs = 182 g

8 moles weigh = 8× 182

=\mathfrak{\blue {\boxed{\underline {1456 \: grams}}}}

or

\mathfrak{\blue {\boxed{\underline {1. 46 \:kg }}}}

5 0
2 years ago
A sulfuric acid solution containing 571.3 g of h2so4 per liter of aqueous solution has a density of 1.329 g/cm3. Part a calculat
loris [4]

Mass percentage of a solution is the amount of solute present in 100 g of the solution.

Given data:

Mass of solute H2SO4 = 571.3 g

Volume of the solution = 1 lit = 1000 ml

Density of solution = 1.329 g/cm3 = 1.329 g/ml

Calculations:

Mass of the given volume of solution = 1.329 g * 1000 ml/1 ml = 1329 g

Therefore we have:

571.3 g of H2SO4 in 1329 g of the solution

Hence, the amount of H2SO4 in 100 g of solution= 571.3 *100/1329 = 42.987

Mass percentage of H2SO4 (%w/w) is 42.99 %

3 0
3 years ago
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