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kodGreya [7K]
3 years ago
6

Objects in free fall near the surface of the Earth experience acceleration of?

Physics
2 answers:
Masja [62]3 years ago
6 0

Answer:

Explanation:

L

julsineya [31]3 years ago
5 0
The answer is (b). free fall due to gravity is 9.8m/s squared, which in this case is expressed as 9.8m/s since there is no exponent to represent m/s squared.
don’t get confused with (c)- that is expressing 9.8 metres to the second per second which is incorrect.
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Which vector has an x-component with a length of 4?
Masja [62]

Answer:ITS Y

Explanation:

6 0
4 years ago
In a pig-calling contest, a caller produces a sound with an intensity level of 60 db. how many such callers would be required to
zloy xaker [14]

The imaginary second level is 60 dB more intense than the real level of the caller.

60 dB means a multiplication of  10⁶  = <em>1 million.</em>

That's how many equally-talented callers it would take to be 60 dB louder than him.

7 0
3 years ago
Helppppo please help help I have no time quick I’m in the exam
Sunny_sXe [5.5K]

Answer:

D

Explanation:

calculate effective resistance of the resistors

= 80 + 120

= 200

overall resistance = 48 ohms

so overall current flowing through circuit

I = V / R

I = 12 / 200

I = 0.06 A

since circuit is in series, current is same at every point so...

potential difference across 80 = R x I

= 80 x 0.06

answer is potential difference = 4.8 V

hope this helps

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5 0
3 years ago
An aluminum wire having a cross-sectional area equal to 3.90 10-6 m2 carries a current of 6.00 A. The density of aluminum is 2.7
stich3 [128]

Answer:

Vd = 1.597 ×10⁻⁴ m/s

Explanation:

Given: A = 3.90×10⁻⁶ m², I = 6.00 A, ρ = 2.70 g/cm³

To find:

Drift Velocity Vd=?

Solution:

the formula is Vd = I/nqA         (n is the number of charge per unit volume)

n = No. of electron in a mole ( Avogadro's No.) / Volume

Volume = Molar mass / density   ( molar mass of Al =27 g)

V = 27 g / 2.70 g/cm³ = 10 cm³ = 1 × 10 ⁻⁵ m³

n= (6.02 × 10 ²³) / (1 × 10 ⁻⁵ m³)

n= 6.02 × 10 ²⁸

Now

Vd = (6A) / (  6.02 × 10 ²⁸ ×  1.6 × 10⁻¹⁹ C ×  3.9×10⁻⁶ m²)

Vd = 1.597 ×10⁻⁴ m/s

6 0
3 years ago
How do air bags help us in a wreck?
andrew-mc [135]
It help protect you from coming out the car when you are in a accident
7 0
3 years ago
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