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Marina CMI [18]

2 years ago

8

An ideal step-down transformer is needed to reduce a primary voltage of 120 V to 6.0 V. What must be the ratio of the number of

turns in the secondary to the number of turns in the primary

1 answer:

Julli [10]2 years ago

7 0

Answer:

$N_s : N_p = 20 : 1$

Explanation:

From the question we are told that

The primary voltage is $V_p = 120 \ V$

The secondary voltage is $V_s = 6 \ V$

Generally from the transformer equation we have that

$\frac{V_p}{V_s} = \frac{N_p}{N_s}$

So

$\frac{120}{6} = \frac{N_p}{N_s}$

=> $\frac{N_p}{N_s} = 20$

Therefore the ratio of the number of turns in the secondary to the number of turns in the primary is

$N_s : N_p = 20 : 1$

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