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Masja [62]
3 years ago
6

Which of the following methods is the most effective in determining muscular strength if you do not want to worry about selectin

g the wrong weight?
Physics
2 answers:
padilas [110]3 years ago
9 0
Predicting 1RM is the answer <span />
kotegsom [21]3 years ago
4 0

Predicting 1 RM is the most effective method in determining muscular strength if you do not want to worry about selecting the wrong weight. The correct answer is C.
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Where on the electromagnetic spectrum is visible light found?
liubo4ka [24]
D. between radio waves and microwaves
7 0
3 years ago
When a 5.0kg cart undergoes a 2.2m/s increase in speed, what is the impulse of the cart
Karolina [17]

Answer:

11.0 kg m/s

Explanation:

The impulse exerted on the cart is equal to its change in momentum:

I=\Delta p=m\Delta v

where

m = 5.0 kg is the mass of the cart

\Delta v=2.2 m/s is its change in speed

Substituting numbers into the equation, we find

I=(5.0kg)(2.2 m/s)=11 kg m/s

7 0
3 years ago
Read 2 more answers
A motorcycle is traveling east at a rate of 56mph.it take 6.7 s for it to decrease its speed to 35mph. How far does the motorcyc
Phantasy [73]
Initial speed = 56mph
Final speed = 35mph

Time taken = 6.7seconds...

Converting the time to hour.. Divide by 3600..
= 6.7/3600

=0.00186hour..

Acceleration = v-u/t

a = 35-56/0.00186
a = -11283.6mph²

The negative sign shows that it decelerated...

V² = u²+2as

(35)² = (56)² + 2×-11283.6×s
Where s is the distance covered within that time...

1225 = 3136 - 22567.2s

22567.2s = 3136-1225

22567.2s = 1911

S = 1911/22567.2

S = 0.08468miles...

But at the end of the question we were made to understand that 1miles = 5280ft

Therefore 0.08468miles = (0.08468×5280)ft

= 447. 11feets...

Which is approximately 447ft.....


Hope this helped.... ?
8 0
3 years ago
A girl is standing still in the middle of a baseball field. The girl catches the baseball and begins to move in the same directi
marusya05 [52]
A. inelastic, since the girl moves in the same direction as the thrown ball
5 0
3 years ago
Read 2 more answers
A mass m = 550 g is hung from a spring with spring constant k = 2.8 N/m and set into oscillation at time t = 0. A second, identi
riadik2000 [5.3K]

Answer:

The second system must be set in motion t=0.70s seconds later

Explanation:

The oscillation time, T, for a mass, m, attached to spring with Hooke's constant, k, is:

T=2\pi\sqrt(\frac{m}{k} )

One oscillation takes T secondes, and that is equivalent to a 2π phase. Then, a difference phase of π/2=2π/4, is equivalent to a time t=T/4.

If the phase difference π/2 of the second system relative to the first oscillator. The second system must be set in motion t=\frac{\pi}{2}\sqrt(\frac{m}{k})=\frac{\pi}{2}\sqrt(\frac{0.55}{2.8}= 0.70s) seconds later

6 0
3 years ago
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