Answer:
When 22.0 g of water is heated from 17 °C to 100 °C what amount of heat absorbed?
When 22.0 g of water is heated from 17 °C to 100 °C water absorbed 7643.64 j heat.
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Given data:
Mass of water = 22.0 g
Initial temperature = 17°C
Final temperature = 100°C
Solution:
ΔT = T₂ -T₁
ΔT = 100°C - 17 °C= 83°C
Q = m.c. ΔT
Q = 22 g× 4.186 j/g °C × 83 °C
Q = 7643.64 j
It means water require more heat which is 7643.64 j to increase its temperature from 17 °C
to 100 °C
.
