The empirical formula of this compound is equal to
.
<h3>
Empirical formula</h3>
To calculate the empirical formula of a compound, it is necessary to know the number of moles present.
Therefore, we will use the molar mass of iron and oxygen to find the amount of moles, so that:






Finally, as the empirical formula is composed of integers numbers of moles, just multiply the values by the smallest common factor to transform into an integer, so that:
O => 
Fe => 
So, the empirical formula of this compound is equal to 
Learn more about empirical formula in: brainly.com/question/1363167
Answer:
2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Explanation:
Given data:
Mass of sample = 142.1 g
Initial temperature = 25.5°C
Final temperature = 46°C
Specific heat capacity of Al = 0.90 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 46°C - 25.5°C
ΔT = 20.5°C
Q = 142.1 × 0.90 J/g.°C × 20.5°C
Q = 2621.75 j
Thus, 2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Answer:
Explanation:
<u>1) Arrhenius equation</u>
Arrhenius equation shows the relation between activation energy, temperature, and the equilibrium constant.
This is the equation:

Where:
- K is the equilibrium constant,
- A is the frequency factor,
- Ea is the activation energy (in J/mol),
- T is the temperature in kelvins (K), and
- R is the universal constant.
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<u>2) Substitute, using the right units, and compute:</u>
- A = 4.20 × 10¹² (dimensionless)
- Ea = 67.0 kJ/mol = 67,000 J/mol
- T = 24.0°C = 24.0 + 273.15 K = 297.15 K
- R = 8.314 J/K mol

Answer:
it's lead (ii) nitrate the name
Yes, it is 80%. Hope this helps!