Answer:
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The first ionization energy is the energy that the atom lost its first electrons. The energy decrease and the atom is more reactive. So from highest to lowest is Li>Na>K>Rb.
The chemical reaction would be written as:
2Na + Cl2 = 2NaCl
Since we are given the amounts of the reactants available for reaction, we have to determine the limiting reactant. And use this amount to calculate for the theoretical yield.
55 g Na ( 1 mol / 22.99 g ) = 2.39 mol Na
67.2 f Cl2 ( 1 mol / 70.9 g ) = 0.95 mol Cl2
Therefore, the limiting reactant would be Cl2 since it is the one consumed completely.
0.95 Cl2 ( 1 mol NaCl / 1 mol Cl2) = 0.95 NaCl produced from the reaction
