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Harman [31]
3 years ago
15

What explanation from the evidence within the chemical equation BEST supports the idea that matter is conserved in a chemical re

action? A There are the same number of atoms of oxygen and hydrogen in the reactants as there are in the products. B There are the same number of elements in the reactants as there are in the products. C More reactants, hydrogen and oxygen, were added to make the product, water. D Two reactants, hydrogen and oxygen, combined to make one product, water.
Chemistry
2 answers:
Olin [163]3 years ago
5 0

Answer:

A There are the same number of atoms of oxygen and hydrogen in the reactants as there are in the products.

Explanation:

Matter is conserved in a chemical equation if there are no loss of atoms. That means, total number of atoms of elements must be the same as the total number of element on the product side. The correct option is;

A. There are the same number of atoms of oxygen and hydrogen in the reactants as there are in the products.

Verdich [7]3 years ago
3 0

Answer:

its A. i just did dat

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What types of emergency situations could rescue workers be in that would make it difficult for them to get energy to their elect
artcher [175]

Answer:

Large-scale natural disasters

Explanation:

The emergency situation that rescue workers could be in that would make it difficult for them to get energy to their electrical devices is "Large-scale natural disasters"

Large-scale natural disasters are very destructive and devastating. Their impact and effect can range from destruction of infrastructures, properties, social amenities and even ecosystems. When such disasters break out, they destroy things and which leads to difficulty in accessing certain amenities. Rescue workers even find it difficult to access energy for their electrical devices - because there is power outage.

Some of these large-scale natural disasters are earthquakes, tornadoes, hurricanes, floods, etc.

4 0
3 years ago
Which of the following has the smallest heat capacity?
musickatia [10]
What are the options?
7 0
3 years ago
Read 2 more answers
Calculate the mass fraction of sodium chloride in the solution if 20 g of it is dissolved in 300 ml of water.
MA_775_DIABLO [31]

The mass fraction of sodium chloride is 0.0625

<h3>What is the mass fraction of sodium chloride in the solution?</h3>

The mass fraction of sodium chloride is the ratio of the mass of sodium chloride to the total mass of the solution.

The mass fraction of sodium chloride is determined as follows;

mass of sodium chloride = 20 g

  • mass of water = volume * density

density of water = 1 g/mL

volume of water = 300 mL

mass of water = 300 mL * 1 g/mL

mass of water = 300 g

total mass of solution = 20 + 300 = 320 g

mass fraction of sodium chloride = 20/320

mass fraction of sodium chloride = 0.0625

Learn more about mass fraction at: brainly.com/question/14783710

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5 0
1 year ago
Consider a sample of 3.5 mol of N2(g) at T1 = 350 K, that undergoes a reversible and adiabatic change in pressure from p1 = 1.50
devlian [24]

Answer:

Part A is just T2 = 58.3 K

Part B ∆U = 10967.6 x C_{V} You can work out C_{V}

Part C

Part D

Part E

Part F

Explanation:

P = n (RT/V)

V = (nR/P) T

P1V1 = P2V2

P1/T1 = P2/T2

V1/T1 = V2/T2

P = Pressure(atm)

n = Moles

T = Temperature(K)

V = Volume(L)

R = 8.314 Joule or 0.08206 L·atm·mol−1·K−1.

bar = 0.986923 atm

N = 14g/mol

N2 Molar Mass 28g

n = 3.5 mol N2

T1 = 350K

P1 = 1.5 bar = 1.4803845 atm

P2 = 0.25 bar = 0.24673075 atm

Heat Capacity at Constant Volume

Q = nCVΔT

Polyatomic gas: CV = 3R

P = n (RT/V)

0.986923 atm x 1.5 = 3.5 mol x ((0.08206 L atm mol -1 K-1 x 350 K) / V))

V = (nR/P) T

V = ((3.5 mol x 0.08206 L atm mol -1 K-1)/(1.5 x 0.986923 atm) )x 350K

V = (0.28721/1.4803845) x 350

V = 0.194 x 350

V = 67.9036 L

So V1 = 67.9036 L

P1V1 = P2V2

1.4803845 atm x 67.9036 L = 0.24673075 x V2

100.52343693 = 0.24673075 x V2

V2 = P1V1/P2

V2 = 100.52343693/0.24673075

V2 = 407.4216 L

P1/T1 = P2/T2

1.4803845 atm / 350 K = 0.24673075 atm / T2

0.00422967 = 0.24673075 /T2

T2 = 0.24673075/0.00422967

T2 = 58.3 K

∆U= nC_{V} ∆T

Polyatomic gas: C_{V} = 3R

∆U= nC_{V} ∆T

∆U= 28g x C_{V} x (350K - 58.3K)

∆U = 28C_{V} x 291.7

∆U = 10967.6 x C_{V}

5 0
3 years ago
1. Most of the chemicals included in your General Chemistry Lab kit can be discarded down a drain. Describe a situation in which
Tju [1.3M]

Answer: Chemicals like acids and bases are harmful and must be neutralized before draining.

Explanation:

A strong acid or strong base is required to be diluted or neutralized before it is discarded in the drain as if is discarded without diluting and neutralization it can spill and splash from sink or drain and can harm people in chemistry lab, moreover the fumes of the discarded chemical on spilling can cause respiratory tract burning and can even cause fire hazard so it must be converted into less harmful form and then must be drained.  

5 0
2 years ago
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