Find total surface area of this cone

Kevin is looking for a job as a graphic designer. One ad lists a job that pays 64.6K. Another job he found has a weekly salary o

Sergeu [11.5K]

Answer:

The difference between the two weekly salaries is $122

Step-by-step explanation:

One job pays $64,600 per year. Since there are 52 weeks in a year, the weekly salary for this job is the quotient: $64600/52 = $1242.31 which rounded to the nearest dollar gives: $1242 per week

The other job pays $1120 per week. Therefore the difference in weekly salary for the two is:

$1242 - $1120 = $122

5 0

3 years ago

The math club is selling gift wrap for a funraiser. They sold 45 rolls of soild wrapping paper at $4 each and rolls of patterned

Lunna [17]

4 * 45 = 180

265 - 180 = 85

85/5 = 17

They sold 17 rolls of patterned wrapping paper.

7 0

3 years ago

Select the correct answer.

marishachu [46]

Answer:

$M = \log(10000)$

Step-by-step explanation:

Given

$M = \log(\frac{I}{I_o})$

$I = 10000I_o$ ---- intensity is 10000 times reference earthquake

Required

The resulting equation

We have:

$M = \log(\frac{I}{I_o})$

Substitute the right values

$M = \log(\frac{10000I_o}{I_o})$

$M = \log(10000)$

5 0

2 years ago

A) double a number, then add 3

Alinara [238K]

Answer:

a) 2x+3

b) 5x-7

c) 2x-10

d) 3x/2

Step-by-step explanation:

the number considered is x

8 0

2 years ago

Triangle ABC has vertices at A(2,3),B(-4,-3) and C(2,-3) find the coordinates of each point of concurrency.

dem82 [27]

Answer:

Circumcenter =(-1,0)

Orthocenter =(2,-3)

Step-by-step explanation:

Given : Points A = (2,3), B = (-4,-3), C = (2,-3)

Formula used :

→Mid point of two points- $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

→Slope of two points - $\frac{y_2-y_1}{x_2-x_1})$

→Perpendicular of a line = $\frac{-1}{slope of line})$

Circumcenter- The point where the perpendicular bisectors of a triangle meets.

Orthocenter-The intersecting point for all the altitudes of the triangle.

To find out the circumcenter we have to solve any two bisector equations.

We solve for line AB and AC

So, mid point of AB = $(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)$

Slope of AB = $\frac{-3-3}{-4-2}=1$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of the perpendicular bisector = -1

Equation of AB with slope -1 and the coordinates (-1,0) is,

(y – 0) = -1(x – (-1))

y+x=-1………………(1)

Similarly, for AC

Mid point of AC = $(\frac{2+2}{2},\frac{3-3}{2})=(2,0)$

Slope of AC = $\frac{-3-3}{2-2}=\frac{-6}{0}$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of the perpendicular bisector = 0

Equation of AC with slope 0 and the coordinates (2,0) is,

(y – 0) = 0(x – 2)

y=0 ………………(2)

By solving equation (1) and (2),

put y=0 in equation (1)

y+x=-1

0+x=-1

⇒x=-1

So the circumcenter(P)= (-1,0)

To find the orthocenter we solve the intersections of altitudes.

We solve for line AB and BC

So, mid point of AB = $(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)$

Slope of AB = $\frac{-3-3}{-4-2}=1$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of CF = -1

Equation of AB with slope -1 and the coordinates (-1,0) gives equation CF

(y – 0) = -1(x – (-1))

y+x=-1………………(3)

Similarly, mid point of BC = $(\frac{-4+2}{2},\frac{-3-3}{2})=(-1,-3)$

Slope of AB = $\frac{-3+3}{-4-2}=0$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of AD = 0

Equation of AB with slope 0 and the coordinates (-1,-3) gives equation AD

(y-(-3)) = 0(x – (-1))

y+3=0

y=-3………………(4)

Solve equation (3) and (4),

Put y=-3 in equation (3)

y+x=-1

-3+x=-1

x=2

Therefore, orthocenter(O)= (2,-3)

7 0

3 years ago