Answer:
5.231 L.
Explanation:
- Molarity is the no. of moles of solute per 1.0 L of the solution.
<em>M = (no. of moles of KCl)/(Volume of the solution (L))</em>
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M = 6.5 M.
no. of moles of solute = 34.0 mol,
Volume of the solution = ??? L.
∴ (6.5 M) = (34.0 mol)/(Volume of the solution (L))
∴ (Volume of the solution (L) = (34.0 mol)/(6.5 M) = 5.231 L.
Answer:
Any binary molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.
Explanation:
Going down in a group increases the atomic radius and a greater atomic radius implyes greater ionic radius.
When ionization takes place in these compounds they yelds protons (hidrogen ion) and an lewis base (anion). The greater the ionic radius the greater its stability, thus the periodic tendency is increaing the acidity of binary hidrogen compounds when going down a group. On the other hand going up a group decreases acidity, so any molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.
The precipitate that is most likely formed from a solution containing Ba+2, Li+, OH-1, and CO3^-2 is BaCO3.
This is because carbonates of all metals except sodium, Lithium potassium (group 1) and ammonium are insoluble in water. Hydroxides of sodium, Lithium, potassium and ammonium are very soluble in water, calcium and barium are moderately soluble. Ba(CO3) is insoluble in water and therefore forms a precipitate.
Answer: The answer is blue, white, yellow-white, orange.
Explanation: These are the two basic reasons for different star colors:
Temperature – cooler stars are red, warmer ones are orange through yellow and white. The hottest stars shine with blue light
Age – As a star ages it produces different chemicals which burn at different temperatures. We can use a star’s color to show its relative age
Answer:
3
Explanation:
NaCl + AgNO₃ ———> NaNO₃ + AgCl.
Firstly, we will need to calculate the number of moles of AgCl produced. That is equal to the mass produced divided by the molar mass of AgCl.
The molar mass of AgCl = 108 + 35.5 = 143.5g/mol
The number of moles is thus 1.32/143.5 = 0.0092 moles
Since silver nitrate and silver chloride contains one atom of silver, it is only possible that their mole ratios are equal. Hence we say that 0.0092 moles of silver nitrate hydrate was dissolved.
Now we go on to calculate the molar mass of the silver nitrate hydrate.
The molar mass is simply the mass divided by the number of moles.
That is 2.06/0.0092 = 223.9 = 224g/mol
We can now calculate the value of x from here.
AgNO3.xH2O
(108 + 14 + 48) + x(2+ 16) = 224
170 + 18x = 224
18x = 224 - 170 = 54
18x = 54
x = 54/18 = 3
