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Goryan [66]
3 years ago
15

I’m like kinda bad at physics so ya please help

Physics
1 answer:
uysha [10]3 years ago
8 0

Answer:

99 joules.

Explanation:

Let m denotes mass of the object and v denotes velocity.

If mass has units of kilograms and the velocity has units of meters per second then the kinetic energy has units of joules.

Kinetic energy is an energy possessed by a body in motion.

Mass (m) = 99 kg

Velocity (v) = 2 m/s

To find kinetic energy, use the following formula:

Kinetic energy = \frac{1}{2}mv^2=\frac{1}{2}(99)(2)=99 joules

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A block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp
GuDViN [60]

The work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.

<h3>What is work done?</h3>

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

Given is  a block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp with respect to the horizontal is θ = 23.5° and the length of the ramp is l = 14.1 m.

From the Newton's law of motion,

ma =F-mg sinθ =0

So, the force F = mg sinθ

Plug the values, we get

F = 620N x sin 23.5°

F = 247.224 N

Work done by motor is  W= F x d

The force is equal to the weight F = mg

So, W = 247.224 x 14.1

W = 3.486 kJ

Thus, the work done by the force in pulling the block all the way to the top of the ramp is  3.486 kJ.

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2 years ago
1) if you could eliminate one item from your diet to improve your heath, what would it be?
Makovka662 [10]

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What is voltage and current?
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A car starts from rest and travels for 5.0 s with a uniform acceleration of +1.5 m/s2 . The driver then applies the brakes, caus
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The final velocity of the car is +1.5 m/s.

Explanation:

We have to divide the problem into two parts.

In the first part, the car starts from rest and accelerates for 5.0 s. We can find the final velocity of the car after this first part using the suvat equation:

v = u +at

where

v is the final velocity

u = 0 is the initial velocity

a=+1.5 m/s^2 is the acceleration

t = 5.0 s is the time

Substituting,

v=0+(1.5)(5.0)=7.5 m/s

In the second part, the brakes are applied, so the car decelerates for 3.0 s, and the final velocity is given by

v' = v + at

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v' is the final velocity

v = 7.5 m/s is the velocity at the beginning of this part

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t = 3.0 s is the time

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In a race, a runner traveled 12 meters in 4.0 seconds as she accelerated uniformly from rest. The magnitude of the acceleration
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<span>The runner is moving by uniformly accelerated motion, starting from rest (so, his initial velocity is zero). The law of motion of the runner is
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We know the runner has covered a distance of S=12m in t=4.0 s, and if we plug these numbers into the equation, we find the acceleration of the runner: 
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3 years ago
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