Explanation:
उत्तर : गुरुत्वाकर्षण का सार्वत्रिक नियम :
इस विश्व का प्रत्येक पिंड दूसरे पिंड को एक बल से अपनी ओर आकर्षित करता है जो दोनों पिंडों के द्रव्यमानों के गुणनफल के समानुपाती होता है तथा उनके बीच की दूरी के वर्ग के व्युत्क्रमानुपाती होता
Answer:
The formula weight of the compound is
46.069 g/mol.
Explanation:
Determine the molar mass from the empirical formula (C2H6O) by multiplying the molar mass of each element in the compound by the number of atoms of it and adding the resulting masses of the elements:
molar mass of C2H6O = (2 × 12.011 g/mol) + (6 × 1.008 g/mol) + (1 × 15.999 g/mol) = 46.069 g/mol.
Answer: <u><em>Hope this helps</em></u>
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<h3>
Explanation:</h3><h3>
<u><em>
The growing and flowering seasons of plants will start earlier as a result of an earlier spring caused by warmer conditions. The growing and flowering season will most likely also last longer, resulting in increased plant growth.</em></u></h3><h3><u><em /></u></h3>
<span>According to Georgia Perimeter College, </span>tap water<span> is not </span>heterogeneous.Heterogeneous mixtures<span> have at least two substances, and viewers can see what is in it. </span>Tap water<span> is </span>homogeneous<span>, as </span>homogeneous mixtures<span> have at least two substances in them, but viewers cannot see them.</span>
Answer:
6.2g of NaBr are produced
Explanation:
The reaction of HBr with NaOH occurs as follows:
HBr + NaOH → NaBr + H2O
<em>Where 1 mole of each reactant produce 1 mole of NaBr</em>
To solve this question we need to find the moles of each reactant using their molar mass. With moles we can find limiting reactant and the moles (And mass) of NaBr produced, as follows:
<em>Moles HBr -Molar mass: 80.9119g/mol)-</em>
4.9g * (1mol/80.9119g) = 0.0606 moles HBr
<em>Moles NaOH -Molar mass: 40g/mol-</em>
3.86g * (1mol/40g) = 0.0965 moles NaOH
As the reaction is 1:1 and the moles of HBr < Moles NaOH, the limiting reactant is HBr and moles of NaBr produced are 0.0606 moles.
The mass of NaBr (Molar mass: 102.894g/mol) is:
0.0606 moles * (102.894g/mol) =
<h3>6.2g of NaBr are produced</h3>