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Anna007 [38]
3 years ago
15

This picture represents the electric field diagram between two particles with static charges. Do the two particles have the same

charge? If the particles are free to move, what affect will the two particles have on each other? If a third particle was added to this field with a positive charge, what would it be attracted to? If an uncharged particle was placed between A and B, which way would it move?​

Physics
1 answer:
dexar [7]3 years ago
7 0

Answers:

No, They will attract each other, B, and neither direction

Explanation:

Since the two already presented particles in the diagram represent both opposing charges due to the direction of the arrows (the arrows facing away from the particle shows a positive charge and the particles facing towards the particle show a negative charge), not only because of this but as the arrows between the particles show an attracting magnetic field, then it can be concluded that the particles will attract to each other and if another particle was introduced into the diagram of a positive charge, then it would attract to the negatively charged particle. If you have any questions or need further explanation, please comment below. E2021, have a great day.

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The general direction in which a graph is moving is called a(n)
Allisa [31]

Answer:

i think correct

Explanation:

6 0
2 years ago
A motorcycle rides on the vertical walls around the perimeter of a large circular room. The friction coefficient between the mot
igomit [66]

Answer:

option D

Explanation:

given,

coefficient of friction between wall and tire = µ

speed of motorcycle = s

friction force = f = μ N

where normal force will be equal to centripetal force

N = \dfrac{mv^2}{r}

for motorcycle to not to slip weight should equal to the centripetal force

 now,

m g =\mu \dfrac{mv^2}{r}

\mu =\dfrac{rg}{s^2}

where "rg" is constant

\mu\ \alpha \ \dfrac{1}{s^2}

\mu\ \alpha \ s^{-2}

Hence, the correct answer is option D

   

7 0
3 years ago
Suppose you have two small pith balls that are 5.5 cm apart and have equal charges of -29 nc?
zysi [14]
The question is missing, however, I guess the problem is asking for the value of the force acting between the two balls.

The Coulomb force between the two balls is:
F= k_e \frac{ q_1 q_2}{r^2}
where k_e=8.99\cdot10^9~N m^2 C^{-2} is the Coulomb's constant, q_1=q_2=29~nC=29\cdot 10^{-9}~C is the intensity of the two charges, and r=5.5~cm=0.055~m is the distance between them.

Substituting these numbers into the equation, we get
F=2.5~10^{-3}~N

The force is repulsive, because the charges have same sign and so they repel each other.
6 0
3 years ago
Does an eclipse occur every time the moon is in the new or full moon phase?
harina [27]

Answer:

solar eclipse mostly occurs when the moon gets between Earth and the sun, and the moon casts a shadow over Earth. A solar eclipse can only take place at the phase of new moon, when the moon passes directly between the sun and Earth and its shadows fall upon Earth's surface.

7 0
3 years ago
Read 2 more answers
Si tu velocidad al caminar es 0,3 m/s. Determina el tiempo que demorarias en llegar al sol en horas (REALIZAR TRANSFORMACIÓN DE
Contact [7]

Answer:

138,516,546.9 horas.

Explanation:

Tenemos que usar la ecuación:

Velocidad = distancia/tiempo

Acá tenemos:

Velocidad = 0.3m/s

distancia = 149597870700 m

y queremos resolver la ecuación para el tiempo:

0.3m/s =  149597870700m/tiempo.

tiempo =  149597870700m/(0.3m/s) = 498,659,569,000 s

y sabemos que una hora tiene 3600 segundos, entonces si queremos transformar de segundos a horas tenemos:

498,659,569,000 s = (498,659,569,000/3600) h = 138,516,546.9 horas.

6 0
3 years ago
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