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nexus9112 [7]
2 years ago
15

How shadows are formed?​

Physics
1 answer:
Y_Kistochka [10]2 years ago
4 0

Answer:

Shadows are formed when an opaque object or material is placed in the path of rays of light. The opaque material does not let the light pass through it. The light rays that go past the edges of the material make an outline for the shadow.

Explanation:

Hope it is helpful.....

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When you listen to the radio watch TV or cook food in the microwave you're using a device that makes use of man-made electric ma
saul85 [17]

Answer:

the false statements

Explanation:

Radio waves, Tw or microndasm are produced by the man with different instruments, so to detect them we use an artifact that detects electrical waves

From  the false statements

5 0
3 years ago
A large uniform chain is hanging from the ceiling, supporting a block of mass 46 kg. The mass of the chain itself is 19 kg, and
docker41 [41]

Answer:

T = 451.26 N

Explanation:

It is given that,

The mass of block, m = 46 kg

Mass of the chain, m' = 19 kg

Length of the chain, l = 1.9 m

Let T is the the tension in the chain at the point where the chain is supporting the block. It is clearly equal to the product of mass and acceleration.

T=mg

T=46\ kg\times 9.81\ m/s^2

T = 451.26 N

So, the tension in the chain at the point where the chain is supporting the block is 451.26 N. Hence, this is the required solution.

4 0
3 years ago
How much power does it take to do 500J of work in 10 sec
tatuchka [14]
P=w/t
so the answer is 500/10=50
8 0
2 years ago
Read 2 more answers
George walks to a friends house. He walks 750 meters north, then realizes he walked too far. He turns around and walks 250 meter
Nostrana [21]

Answer: 77 m/s in 2 significant figures

Explanation:

Total distance traveled (d) = 750 + 250 = 1000m

Time taken (t) = 13 s

Speed (s) = ?

Now,

s = d/t

s = 1000/13

s = 77 m/s in 2 significant figures

4 0
3 years ago
At a certain distance from the center of the Earth, a 0.4-kg object has a weight of 2.0 N. (a) Find this distance. (b) If the ob
Alika [10]

Answer:

a) The distance of the object from the center of the Earth is 8.92x10⁶ m.

b) The initial acceleration of the object is 5 m/s².

Explanation:

a) The distance can be found using the equation of gravitational force:

F = \frac{GMm}{r^{2}}

Where:

G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²

M: is the Earth's mass =  5.97x10²⁴ kg  

m: is the object's mass = 0.4 kg

F: is the force or the weight = 2.0 N    

r: is the distance =?

The distance is:

r = \sqrt{\frac{GMm}{F}} = \sqrt{\frac{6.67 \cdot 10^{-11} Nm^{2}/kg^{2}*5.97 \cdot 10^{24} kg*0.4 kg}{2.0 N}} = 8.92 \cdot 10^{6} m      

Hence, the distance of the object from the center of the Earth is 8.92x10⁶ m.

         

b) The initial acceleration of the object can be calculated knowing the weight:              

W = ma                                                  

Where:            

W: is the weight = 2 N

a: is the initial acceleration =?          

a = \frac{W}{m} = \frac{2 N}{0.4 kg} = 5 m/s^{2}

Therefore, the initial acceleration of the object is 5 m/s².

           

I hope it helps you!    

4 0
2 years ago
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